RE: [flexcoders] Re: *** So you think you know ActionScript? (Read original post first) ***

2009-08-13 Thread Tracy Spratt
Ah, I see something I missed at first.  This example is using literal xml,
so the null IS getting interpreted by AS as null and not as a string.  I bet
it would be different if you did:

var xml:XML = XML(outerinnernull/inner/outer);

 

Even so I am still surprised because the null should be the text node and
the expression should return an XMLList with zero length.  Very interesting.

 

Tracy Spratt,

Lariat Services, development services available

  _  

From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On
Behalf Of jaywood58
Sent: Thursday, August 13, 2009 12:48 PM
To: flexcoders@yahoogroups.com
Subject: [flexcoders] Re: *** So you think you know ActionScript? (Read
original post first) ***

 

  

--- In flexcod...@yahoogro mailto:flexcoders%40yahoogroups.com ups.com,
Tracy Spratt tr...@... wrote:

 _ 
 
 From: flexcod...@yahoogro mailto:flexcoders%40yahoogroups.com ups.com
[mailto:flexcod...@yahoogro mailto:flexcoders%40yahoogroups.com ups.com]
On
 Behalf Of Paul Andrews
 Sent: Wednesday, August 12, 2009 9:33 PM
 To: flexcod...@yahoogro mailto:flexcoders%40yahoogroups.com ups.com
 Subject: Re: [flexcoders] *** So you think you know ActionScript? (Read
 original post first) ***
 
 
 
 
 
 Dave Glasser wrote:
  Consider this code snippet:
 
  var xml:XML = outerinnernull/inner/outer;
  var xmlList:XMLList = xml.inner;
  trace(xmlList == null);
 
  What does the trace statement output, true or false, and why?
 
  Please provide an answer without running the code (of course) and,
better
 yet, without consulting any documentation, or any of the other answers
that
 may have been posted already (if you read the list in chronological
order.)
 Pretend it's a job interview question and you have to give it your best
shot
 off the top of your head.
 
  And also, if you don't mind, don't top-post your answer, so that if
 someone does read your answer before the original post, they might get a
 chance to answer without having seen yours first.
  
 
 xmlList is set to point at somthing which isn't a list, so I think the 
 trace statement will not be reached. That's my 02:31AM thought..
 
 
 
 All e4x expressions return an XMLList. It can be empty but is never a
null.
 Besides, the characters. null in a text node are just a string. null
in
 an AS comparison is a special value. The trace will display false.
 Trace(xmllist.text() ==null ); //would return true.
 
 
 
 Tracy Spratt,
 
 Lariat Services, development services available


Like Tracy, I thought it would return false, for the same reason -- that
innernull/inner would be interpreted as a string. Was surprised when I
ran the code and saw true. What's going on? It seems like the AS decoder
recognizes null as a special case. 





RE: [flexcoders] Re: *** So you think you know ActionScript? (Read original post first) ***

2009-08-13 Thread Dave Glasser
Actually, no. It would interpret it as null if it were enclosed in curly braces 
like this:



var xml:XML = outerinner{null}/inner/outer;



And even then, null might be converted to its String value, null, as
the content of the element. I'd have to try it to know for sure.



In the example I gave, the content of the element is a String consisting of the 
letters n, u, l and l, in that order.

In any case, the xmlList variable would reference a non-null XMLList object. 
That's easily proven by dereferencing it:

trace(The length is  + xmlList.length());

That would output The length is 1.

--- On Thu, 8/13/09, Tracy Spratt tr...@nts3rd.com wrote:

From: Tracy Spratt tr...@nts3rd.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***
To: flexcoders@yahoogroups.com
Date: Thursday, August 13, 2009, 3:49 PM






 





  







Ah, I see something I missed at
first.  This example is using “literal” xml, so the null IS
getting interpreted by AS as null and not as a string.  I bet it would be
different if you did: 

var xml:XML = XML(“outerinner null/inner /outer”); 

   

Even so I am still surprised because the
null should be the text node and the expression should return an XMLList with
zero length.  Very interesting. 

   



Tracy Spratt, 

Lariat Services, development services
available 











From:
flexcod...@yahoogro ups.com [mailto:flexcoders@ yahoogroups. com] On Behalf Of 
jaywood58

Sent: Thursday, August 13, 2009
12:48 PM

To: flexcod...@yahoogro ups.com

Subject: [flexcoders] Re: *** So
you think you know ActionScript? (Read original post first) *** 



   

   









--- In flexcod...@yahoogro ups.com,
Tracy Spratt  tracy @...
wrote:



 _ 

 

 From: flexcod...@yahoogro ups.com
[mailto:flexcod...@yahoogro ups.com]
On

 Behalf Of Paul Andrews

 Sent: Wednesday, August 12, 2009 9:33 PM

 To: flexcod...@yahoogro ups.com

 Subject: Re: [flexcoders] *** So you think you know ActionScript? (Read

 original post first) ***

 

 

 

 

 

 Dave Glasser wrote:

  Consider this code snippet:

 

  var xml:XML = outerinner null/inner /outer;

  var xmlList:XMLList = xml.inner;

  trace(xmlList == null);

 

  What does the trace statement output, true or false, and why?

 

  Please provide an answer without running the code (of course) and,
better

 yet, without consulting any documentation, or any of the other answers
that

 may have been posted already (if you read the list in chronological
order.)

 Pretend it's a job interview question and you have to give it your best
shot

 off the top of your head.

 

  And also, if you don't mind, don't top-post your answer, so that if

 someone does read your answer before the original post, they might get a

 chance to answer without having seen yours first.

  

 

 xmlList is set to point at somthing which isn't a list, so I think the 

 trace statement will not be reached. That's my 02:31AM thought..

 

 

 

 All e4x expressions return an XMLList. It can be empty but is never a
null.

 Besides, the characters. null in a text node are just a
string. null in

 an AS comparison is a special value. The trace will display false.

 Trace(xmllist. text() ==null ); //would return true.

 

 

 

 Tracy Spratt,

 

 Lariat Services, development services available





Like Tracy , I
thought it would return false, for the same reason -- that innernull /inner
would be interpreted as a string. Was surprised when I ran the code and saw
true. What's going on? It seems like the AS decoder recognizes null
as a special case.  










 

  




 
















RE: [flexcoders] Re: *** So you think you know ActionScript? (Read original post first) ***

2009-08-13 Thread Tracy Spratt
Ok, if you say so.  What is the result of your investigation?

 

It gets kind of complicated because AS does implicit toString() sometimes
which can hide what is really happening.

Do:

trace(xmlList == null);

and

trace(xmlList == null);

return the same result?

 

Tracy Spratt,

Lariat Services, development services available

  _  

From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On
Behalf Of Dave Glasser
Sent: Thursday, August 13, 2009 5:22 PM
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read
original post first) ***

 

  


Actually, no. It would interpret it as null if it were enclosed in curly
braces like this:

var xml:XML = outerinner{null}/inner/outer;

And even then, null might be converted to its String value, null, as the
content of the element. I'd have to try it to know for sure.

In the example I gave, the content of the element is a String consisting of
the letters n, u, l and l, in that order.

In any case, the xmlList variable would reference a non-null XMLList object.
That's easily proven by dereferencing it:

trace(The length is  + xmlList.length());

That would output The length is 1.

--- On Thu, 8/13/09, Tracy Spratt tr...@nts3rd.com wrote:


From: Tracy Spratt tr...@nts3rd.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read
original post first) ***
To: flexcoders@yahoogroups.com
Date: Thursday, August 13, 2009, 3:49 PM

  

Ah, I see something I missed at first.  This example is using literal xml,
so the null IS getting interpreted by AS as null and not as a string.  I bet
it would be different if you did:

var xml:XML = XML(outerinner null/inner /outer);

 

Even so I am still surprised because the null should be the text node and
the expression should return an XMLList with zero length.  Very interesting.

 

Tracy Spratt,

Lariat Services, development services available

  _  

From: flexcod...@yahoogro ups.com [mailto:flexcoders@ yahoogroups. com] On
Behalf Of jaywood58
Sent: Thursday, August 13, 2009 12:48 PM
To: flexcod...@yahoogro ups.com
Subject: [flexcoders] Re: *** So you think you know ActionScript? (Read
original post first) ***

 

  

--- In flexcod...@yahoogro ups.com, Tracy Spratt  tracy @... wrote:

 _ 
 
 From: flexcod...@yahoogro ups.com [mailto:flexcod...@yahoogro ups.com] On
 Behalf Of Paul Andrews
 Sent: Wednesday, August 12, 2009 9:33 PM
 To: flexcod...@yahoogro ups.com
 Subject: Re: [flexcoders] *** So you think you know ActionScript? (Read
 original post first) ***
 
 
 
 
 
 Dave Glasser wrote:
  Consider this code snippet:
 
  var xml:XML = outerinner null/inner /outer;
  var xmlList:XMLList = xml.inner;
  trace(xmlList == null);
 
  What does the trace statement output, true or false, and why?
 
  Please provide an answer without running the code (of course) and,
better
 yet, without consulting any documentation, or any of the other answers
that
 may have been posted already (if you read the list in chronological
order.)
 Pretend it's a job interview question and you have to give it your best
shot
 off the top of your head.
 
  And also, if you don't mind, don't top-post your answer, so that if
 someone does read your answer before the original post, they might get a
 chance to answer without having seen yours first.
  
 
 xmlList is set to point at somthing which isn't a list, so I think the 
 trace statement will not be reached. That's my 02:31AM thought..
 
 
 
 All e4x expressions return an XMLList. It can be empty but is never a
null.
 Besides, the characters. null in a text node are just a string. null
in
 an AS comparison is a special value. The trace will display false.
 Trace(xmllist. text() ==null ); //would return true.
 
 
 
 Tracy Spratt,
 
 Lariat Services, development services available


Like Tracy , I thought it would return false, for the same reason -- that
innernull /inner would be interpreted as a string. Was surprised when I
ran the code and saw true. What's going on? It seems like the AS decoder
recognizes null as a special case. 





RE: [flexcoders] Re: *** So you think you know ActionScript? (Read original post first) ***

2009-08-13 Thread Gordon Smith
Does anybody want to try to figure out what the E4X spec says it should do? 
It's certainly possible that the Player implementation of E4X is doing it wrong.

Gordon Smith
Adobe Flex SDK Team

From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On Behalf 
Of Tracy Spratt
Sent: Thursday, August 13, 2009 3:10 PM
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***


Ok, if you say so.  What is the result of your investigation?

It gets kind of complicated because AS does implicit toString() sometimes which 
can hide what is really happening.
Do:
trace(xmlList == null);
and
trace(xmlList == null);
return the same result?

Tracy Spratt,
Lariat Services, development services available

From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On Behalf 
Of Dave Glasser
Sent: Thursday, August 13, 2009 5:22 PM
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***


Actually, no. It would interpret it as null if it were enclosed in curly braces 
like this:

var xml:XML = outerinner{null}/inner/outer;

And even then, null might be converted to its String value, null, as the 
content of the element. I'd have to try it to know for sure.

In the example I gave, the content of the element is a String consisting of the 
letters n, u, l and l, in that order.

In any case, the xmlList variable would reference a non-null XMLList object. 
That's easily proven by dereferencing it:

trace(The length is  + xmlList.length());

That would output The length is 1.

--- On Thu, 8/13/09, Tracy Spratt tr...@nts3rd.com wrote:

From: Tracy Spratt tr...@nts3rd.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***
To: flexcoders@yahoogroups.com
Date: Thursday, August 13, 2009, 3:49 PM

Ah, I see something I missed at first.  This example is using literal xml, so 
the null IS getting interpreted by AS as null and not as a string.  I bet it 
would be different if you did:
var xml:XML = XML(outerinner null/inner /outer);

Even so I am still surprised because the null should be the text node and the 
expression should return an XMLList with zero length.  Very interesting.

Tracy Spratt,
Lariat Services, development services available

From: flexcod...@yahoogro ups.com [mailto:flexcoders@ yahoogroups. com] On 
Behalf Of jaywood58
Sent: Thursday, August 13, 2009 12:48 PM
To: flexcod...@yahoogro ups.com
Subject: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***



--- In flexcod...@yahoogro 
ups.com/mc/compose?to=flexcoders%40yahoogroups.com, Tracy Spratt  tracy 
@... wrote:

 _

 From: flexcod...@yahoogro 
 ups.com/mc/compose?to=flexcoders%40yahoogroups.com 
 [mailto:flexcod...@yahoogro 
 ups.com/mc/compose?to=flexcoders%40yahoogroups.com] On
 Behalf Of Paul Andrews
 Sent: Wednesday, August 12, 2009 9:33 PM
 To: flexcod...@yahoogro ups.com/mc/compose?to=flexcoders%40yahoogroups.com
 Subject: Re: [flexcoders] *** So you think you know ActionScript? (Read
 original post first) ***





 Dave Glasser wrote:
  Consider this code snippet:
 
  var xml:XML = outerinner null/inner /outer;
  var xmlList:XMLList = xml.inner;
  trace(xmlList == null);
 
  What does the trace statement output, true or false, and why?
 
  Please provide an answer without running the code (of course) and, better
 yet, without consulting any documentation, or any of the other answers that
 may have been posted already (if you read the list in chronological order.)
 Pretend it's a job interview question and you have to give it your best shot
 off the top of your head.
 
  And also, if you don't mind, don't top-post your answer, so that if
 someone does read your answer before the original post, they might get a
 chance to answer without having seen yours first.
 

 xmlList is set to point at somthing which isn't a list, so I think the
 trace statement will not be reached. That's my 02:31AM thought..



 All e4x expressions return an XMLList. It can be empty but is never a null.
 Besides, the characters. null in a text node are just a string. null in
 an AS comparison is a special value. The trace will display false.
 Trace(xmllist. text() ==null ); //would return true.



 Tracy Spratt,

 Lariat Services, development services available


Like Tracy , I thought it would return false, for the same reason -- that 
innernull /inner would be interpreted as a string. Was surprised when I ran 
the code and saw true. What's going on? It seems like the AS decoder recognizes 
null as a special case.




RE: [flexcoders] Re: *** So you think you know ActionScript? (Read original post first) ***

2009-08-13 Thread Dave Glasser

--- On Thu, 8/13/09, Tracy Spratt tr...@nts3rd.com wrote:


Ok, if you say so.  What is the
result of your investigation? 


I just checked, and it does indeed convert null to null. So it's effectively 
the same with or without the curly braces. The element contains a String 4 
characters long.


It gets kind of complicated because AS does
implicit toString() sometimes which can hide what is really happening. 

Do: 

trace(xmlList == null); 

and 

trace(xmlList == “null”); 

return the same result? 

Surprisingly, the second one doesn't compile. It failed with the error:

Error: Comparison between a value with static type XMLList and a possibly 
unrelated type String.

But if it did compile, I would expect it to produce the same result. And just 
to make sure, I was able to compile and run this:

...
var s:* = null
trace(xmlList == s);

and the output was the same as when comparing xmlList to null.



  



RE: [flexcoders] Re: *** So you think you know ActionScript? (Read original post first) ***

2009-08-13 Thread Dave Glasser
By my reading, everything seems to be working how it's supposed to work. But 
how it's supposed to work is very surprising to me. And it's not really E4X 
that's producing the odd behavior, it's the == operator. I'll go ahead and post 
the answer and explanation in my next message.

--- On Thu, 8/13/09, Gordon Smith gosm...@adobe.com wrote:

From: Gordon Smith gosm...@adobe.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***
To: flexcoders@yahoogroups.com flexcoders@yahoogroups.com
Date: Thursday, August 13, 2009, 6:54 PM













 
 
















Does anybody want to try to figure out what the E4X spec says it
should do? It's certainly possible that the Player implementation of E4X is
doing it wrong. 

   

Gordon Smith 

Adobe Flex SDK Team 

   





From:
flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On Behalf Of 
Tracy
Spratt

Sent: Thursday, August 13, 2009 3:10 PM

To: flexcoders@yahoogroups.com

Subject: RE: [flexcoders] Re: *** So you think you know ActionScript?
(Read original post first) *** 





   

   









Ok, if you
say so.  What is the result of your investigation? 

  

It gets
kind of complicated because AS does implicit toString() sometimes which can
hide what is really happening. 

Do: 

trace(xmlList
== null); 

and 

trace(xmlList
== “null”); 

return
the same result? 

  



Tracy
Spratt, 

Lariat
Services, development services available 











From: flexcoders@yahoogroups.com
[mailto:flexcod...@yahoogroups.com] On Behalf Of Dave Glasser

Sent: Thursday, August 13, 2009 5:22 PM

To: flexcoders@yahoogroups.com

Subject: RE: [flexcoders] Re: *** So you think you know ActionScript?
(Read original post first) *** 



  

 
 








 
  
  Actually,
  no. It would interpret it as null if it were enclosed in curly braces like
  this:

  

  var xml:XML = outerinner{null}/inner/outer;

  

  And even then, null might be converted to its String value, null,
  as the content of the element. I'd have to try it to know for sure.

  

  In the example I gave, the content of the element is a String consisting of
  the letters n, u, l and l, in
  that order.

  

  In any case, the xmlList variable would reference a non-null XMLList object.
  That's easily proven by dereferencing it:

  

  trace(The length is  + xmlList.length());

  

  That would output The length is 1.

  

  --- On Thu, 8/13/09, Tracy Spratt tr...@nts3rd.com
  wrote: 
  

  From: Tracy Spratt tr...@nts3rd.com

  Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read
  original post first) ***

  To: flexcoders@yahoogroups.com

  Date: Thursday, August 13, 2009, 3:49 PM 
  
   
   
  
  
  Ah, I
  see something I missed at first.  This example is using “literal” xml,
  so the null IS getting interpreted by AS as null and not as a string.  I
  bet it would be different if you did: 
  var
  xml:XML = XML(“outerinner null/inner /outer”); 
    
  Even so
  I am still surprised because the null should be the text node and the
  expression should return an XMLList with zero length.  Very interesting. 
    
  
  Tracy
  Spratt, 
  Lariat
  Services, development services available 
  
  
  
  
  
  From:
  flexcod...@yahoogro ups.com [mailto:flexcoders@ yahoogroups. com] On
  Behalf Of jaywood58

  Sent: Thursday, August 13, 2009 12:48 PM

  To: flexcod...@yahoogro ups.com

  Subject: [flexcoders] Re: *** So you think you know ActionScript?
  (Read original post first) *** 
  
    
   
   
  
  
  
  --- In flexcod...@yahoogro ups.com, Tracy Spratt
   tracy @... wrote:

  

   _ 

   

   From: flexcod...@yahoogro ups.com [mailto:flexcod...@yahoogro
  ups.com] On

   Behalf Of Paul Andrews

   Sent: Wednesday, August 12, 2009 9:33 PM

   To: flexcod...@yahoogro
  ups.com

   Subject: Re: [flexcoders] *** So you think you know ActionScript? (Read

   original post first) ***

   

   

   

   

   

   Dave Glasser wrote:

Consider this code snippet:

   

var xml:XML = outerinner null/inner
  /outer;

var xmlList:XMLList = xml.inner;

trace(xmlList == null);

   

What does the trace statement output, true or false, and why?

   

Please provide an answer without running the code (of course) and,
  better

   yet, without consulting any documentation, or any of the other answers
  that

   may have been posted already (if you read the list in chronological
  order.)

   Pretend it's a job interview question and you have to give it your best
  shot

   off the top of your head.

   

And also, if you don't mind, don't top-post your answer, so that if

   someone does read your answer before the original post, they might get a

   chance to answer without having seen yours first.



   

   xmlList is set to point at somthing which isn't a list, so I think the 

   trace statement will not be reached. That's my 02:31AM thought..

   

   

   

   All e4x expressions return

RE: [flexcoders] Re: *** So you think you know ActionScript? (Read original post first) ***

2009-08-13 Thread Gordon Smith
Well, the == operator produces a lot of interesting behavior. That's why 
there's a === operator. ☺

Gordon Smith
Adobe Flex SDK Team

From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On Behalf 
Of Dave Glasser
Sent: Thursday, August 13, 2009 4:39 PM
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***


By my reading, everything seems to be working how it's supposed to work. But 
how it's supposed to work is very surprising to me. And it's not really E4X 
that's producing the odd behavior, it's the == operator. I'll go ahead and post 
the answer and explanation in my next message.

--- On Thu, 8/13/09, Gordon Smith gosm...@adobe.com wrote:

From: Gordon Smith gosm...@adobe.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***
To: flexcoders@yahoogroups.com flexcoders@yahoogroups.com
Date: Thursday, August 13, 2009, 6:54 PM

Does anybody want to try to figure out what the E4X spec says it should do? 
It's certainly possible that the Player implementation of E4X is doing it wrong.

Gordon Smith
Adobe Flex SDK Team

From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On Behalf 
Of Tracy Spratt
Sent: Thursday, August 13, 2009 3:10 PM
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***


Ok, if you say so.  What is the result of your investigation?

It gets kind of complicated because AS does implicit toString() sometimes which 
can hide what is really happening.
Do:
trace(xmlList == null);
and
trace(xmlList == “null”);
return the same result?

Tracy Spratt,
Lariat Services, development services available

From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On Behalf 
Of Dave Glasser
Sent: Thursday, August 13, 2009 5:22 PM
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***


Actually, no. It would interpret it as null if it were enclosed in curly braces 
like this:

var xml:XML = outerinner{null}/inner/outer;

And even then, null might be converted to its String value, null, as the 
content of the element. I'd have to try it to know for sure.

In the example I gave, the content of the element is a String consisting of the 
letters n, u, l and l, in that order.

In any case, the xmlList variable would reference a non-null XMLList object. 
That's easily proven by dereferencing it:

trace(The length is  + xmlList.length());

That would output The length is 1.

--- On Thu, 8/13/09, Tracy Spratt tr...@nts3rd.com wrote:

From: Tracy Spratt tr...@nts3rd.com
Subject: RE: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***
To: flexcoders@yahoogroups.com
Date: Thursday, August 13, 2009, 3:49 PM

Ah, I see something I missed at first.  This example is using “literal” xml, so 
the null IS getting interpreted by AS as null and not as a string.  I bet it 
would be different if you did:
var xml:XML = XML(“outerinner null/inner /outer”);

Even so I am still surprised because the null should be the text node and the 
expression should return an XMLList with zero length.  Very interesting.

Tracy Spratt,
Lariat Services, development services available

From: flexcod...@yahoogro ups.com [mailto:flexcoders@ yahoogroups. com] On 
Behalf Of jaywood58
Sent: Thursday, August 13, 2009 12:48 PM
To: flexcod...@yahoogro ups.com
Subject: [flexcoders] Re: *** So you think you know ActionScript? (Read 
original post first) ***



--- In flexcod...@yahoogro ups.com, Tracy Spratt  tracy @... wrote:

 _

 From: flexcod...@yahoogro ups.com [mailto:flexcod...@yahoogro ups.com] On
 Behalf Of Paul Andrews
 Sent: Wednesday, August 12, 2009 9:33 PM
 To: flexcod...@yahoogro ups.com
 Subject: Re: [flexcoders] *** So you think you know ActionScript? (Read
 original post first) ***





 Dave Glasser wrote:
  Consider this code snippet:
 
  var xml:XML = outerinner null/inner /outer;
  var xmlList:XMLList = xml.inner;
  trace(xmlList == null);
 
  What does the trace statement output, true or false, and why?
 
  Please provide an answer without running the code (of course) and, better
 yet, without consulting any documentation, or any of the other answers that
 may have been posted already (if you read the list in chronological order.)
 Pretend it's a job interview question and you have to give it your best shot
 off the top of your head.
 
  And also, if you don't mind, don't top-post your answer, so that if
 someone does read your answer before the original post, they might get a
 chance to answer without having seen yours first.
 

 xmlList is set to point at somthing which isn't a list, so I think the
 trace statement will not be reached. That's my 02:31AM thought..



 All e4x expressions return