Re: More questions on line breaking

2004-12-06 Thread Luca Furini
Finn Bock wrote: Ok, so it isn't really needed when the algorithm is implemented in java. Just by having the previous node linked from within bestActiveNode is enough to keep the inactive nodes alive. So inactiveList can be removed. You are right, I'm going to remove it. Thanks! Regards,

Re: More questions on line breaking.

2004-12-03 Thread Simon Pepping
On Thu, Dec 02, 2004 at 08:42:30PM +0100, Finn Bock wrote: Hi Some more questions. 1) What is inactiveList doing. Nodes are added but never used. It contains all feasible breakpoints except those that are still active, i.e., are still in scope as the start of a line ending at the currently

Re: More questions on line breaking.

2004-12-03 Thread Finn Bock
1) What is inactiveList doing. Nodes are added but never used. [Simon] It contains all feasible breakpoints except those that are still active, i.e., are still in scope as the start of a line ending at the currently considered breakpoint. At the end of the loop the active list only contains nodes

More questions on line breaking.

2004-12-02 Thread Finn Bock
Hi Some more questions. 1) What is inactiveList doing. Nodes are added but never used. 2) If there is no shrink in a line (the case in START alignment) then nodes are never removed from activeList until a forced break element is found. Is that really the intention of the algorithm? It seems