Re: More questions on line breaking

2004-12-06 Thread Luca Furini
Finn Bock wrote: > Ok, so it isn't really needed when the algorithm is implemented in java. > Just by having the previous node linked from within bestActiveNode is > enough to keep the inactive nodes alive. > > So inactiveList can be removed. You are right, I'm going to remove it. Thanks! Regard

Re: More questions on line breaking.

2004-12-03 Thread Finn Bock
1) What is inactiveList doing. Nodes are added but never used. [Simon] It contains all feasible breakpoints except those that are still active, i.e., are still in scope as the start of a line ending at the currently considered breakpoint. At the end of the loop the active list only contains nodes

Re: More questions on line breaking.

2004-12-03 Thread Simon Pepping
On Thu, Dec 02, 2004 at 08:42:30PM +0100, Finn Bock wrote: > Hi > > Some more questions. > > 1) What is inactiveList doing. Nodes are added but never used. It contains all feasible breakpoints except those that are still active, i.e., are still in scope as the start of a line ending at the curre

More questions on line breaking.

2004-12-02 Thread Finn Bock
Hi Some more questions. 1) What is inactiveList doing. Nodes are added but never used. 2) If there is no shrink in a line (the case in START alignment) then nodes are never removed from activeList until a forced break element is found. Is that really the intention of the algorithm? It seems suspe