RE: images, xsl:fo rookie question

[Darren Munt]

On Friday, July 20, Thieler Jens wrote:

I suppose this question to be OT even in fop-user.
Anyhow, study the appended code
and above all study some XSLT tutorials.

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
 xmlns:fo="http://www.w3.org/1999/XSL/Format";>
  <xsl:template match="/">
    <fo:root>
      <xsl:apply-templates />
    </fo:root>
  </xsl:template>
  
  <xsl:template match="//PICTURE">
    <fo:block>
      <fo:external-graphic>
        <xsl:attribute name="src">
          <xsl:text>file:</xsl:text>
          <xsl:value-of select="@source" />
        </xsl:attribute>
      </fo:external-graphic>
    </fo:block>
  </xsl:template>

  <xsl:template match="//PUNCTURE">
    <xsl:variable name="source">
      <xsl:value-of select="@source" />
    </xsl:variable>
    <fo:block>
      <fo:external-graphic src="file:{$source}" />
    </fo:block>
  </xsl:template>
</xsl:stylesheet>

-----Original Message-----
From: Darrel Riekhof [mailto:[EMAIL PROTECTED]]
Sent: Thursday, 2 August 2001 12:01 
To: '[EMAIL PROTECTED]'
Subject: images, xsl:fo rookie question


I can't figure out how to pull a url to an image from my xml file into the
.fo file via xsl.  In my xml file, I have a tag like this:

  <logoURL>http://blah/images/blah.jpg</logoURL>

The .fo examples show inserting an image like this:

  <fo:external-graphic src="http://blah/images/blah.gif"/> 

How do I get an xsl command like this to execute inside the quotes of the
src attrib to pull the url from the xml file?

  <xsl:value-of select="logoURL"/>

Darrel

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