No,
if you put a semicolon in there, you will get wrong syntax,
no matter what the datatype is.
Example:
{$MACRO ON}
{$define Fifteen:=15;}
{$define Twelve:=12;}
...
if HDCOUNT0 >= COUNT0 then X := Fifteen
else X := Twelve;
will generate this Pascal statement:
if HDCOUNT0
Il 12/04/2017 19:54, Bernd Oppolzer ha scritto:
I'm no FPC macro language wizard, but in my believe
you are replacing Positiva with False, followed by a semicolon,
and so you get the error from the compiler.
{$define Positiva:=False}
should probably work.
You are right, I was misled by some
Il 12/04/2017 19:51, Michael Van Canneyt ha scritto:
Try removing the semicolon:
{$define Positiva:=False}
{$define Negativa:=True}
Without semicolon it works!
Thanks a lot.
BTW, do you think that this holds true only for the define of boolean
values?
Hi Guiliano,
I'm no FPC macro language wizard, but in my believe
you are replacing Positiva with False, followed by a semicolon,
and so you get the error from the compiler.
{$define Positiva:=False}
should probably work.
HTH,
kind regards
Bernd
Am 12.04.2017 um 19:39 schrieb Giuliano
On Wed, 12 Apr 2017, Giuliano Colla wrote:
Hi honourable fpc developers!
I found a strange error (both with fpc 2.6.4 and fpc 3.0.0, in Linux
environment)
The following snippet of code:
{$MACRO ON}
{$define Positiva:=False;}
{$define Negativa:=True;}
...
if HDCOUNT0 >= COUNT0
Hi honourable fpc developers!
I found a strange error (both with fpc 2.6.4 and fpc 3.0.0, in Linux
environment)
The following snippet of code:
{$MACRO ON}
{$define Positiva:=False;}
{$define Negativa:=True;}
...
if HDCOUNT0 >= COUNT0 then V_PIU0 := Positiva
else V_PIU0 :=
