Re: bsdlabel offset

2008-03-20 Thread Adam Pordzik

Jerry McAllister wrote:

On Fri, Mar 14, 2008 at 11:40:55AM +0100, Tektonaut wrote:


Hi,

following bsdllabel output caught my attention:

#sizeoffsetfstype   [fsize bsize bps/cpg]
 a:  2097152 04.2BSD 2048 16384 28552 
 b:  4194304   2097152  swap
 c: 3125766420unused0 0 # raw part, don't 
 edit
 d: 33554432   62914564.2BSD 2048 16384 28552 
...


I created this disk with sade or sysinstall. What I'm not sure
about is that partition 'a' has an offset of 0. With an 8k big
/boot/boot I would guess offset should be 16block large.

But since the disk is booting, some boot1 loader ist located at
sector 0 (from the beginning of this slice). How is it assured,
that the first block will never be overwritten? Where is boot1
located, where boot2?

Comparing the first sector with boot and boot1 differs already
at the first char. (and there were no updates so far)


That sector 0 lies outside of the slice block 0. What you are
seeing is not an absolute disk offset, but the offset in to the slice.  


Right, and sector 0 of the bsd-partition (label) begins where
the bsd-partition- starts. Since offset of ads1a is zero, sector 0
ad0s1a is the same as sector 0 of ad0s1.

So my problem was to understand how there can be any room for
boot1+2, if the filesystem start right there. My fault was to assume,
that the ufs-superblock begins at first sector. (see below)


It is possible to create it otherwise but isn't done that
way by default.Nowdays, actually a whole track is held
out, instead of just sector 0 and that is where some of the
fancier MBRs such as GRUB get their extra space to work.
But, the standard FreeBSD MBR sticks to the official standard
of just one sector - which is why it is so plain vanilla.


Since I have no real use for a DOS/MBR-partitiontable, I'd like to
partitionate a dangerously dedicated layout. How would I do
this in a safe way?

I found the answer to my question in sys/ufs/ffs/fh.h: UFS leaves
some sectors free up to the superblock. Dependening on x
that can be 0k, 8k, 32k, 64k or even 256k.

Adam

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Re: bsdlabel offset

2008-03-20 Thread Jerry McAllister
On Thu, Mar 20, 2008 at 04:38:00PM +0100, Adam Pordzik wrote:

 Jerry McAllister wrote:
 On Fri, Mar 14, 2008 at 11:40:55AM +0100, Tektonaut wrote:
 
 Hi,
 
 following bsdllabel output caught my attention:
 
 #sizeoffsetfstype   [fsize bsize bps/cpg]
  a:  2097152 04.2BSD 2048 16384 28552 
  b:  4194304   2097152  swap
  c: 3125766420unused0 0 # raw part, 
  don't edit
  d: 33554432   62914564.2BSD 2048 16384 28552 
 ...
 
 I created this disk with sade or sysinstall. What I'm not sure
 about is that partition 'a' has an offset of 0. With an 8k big
 /boot/boot I would guess offset should be 16block large.
 
 But since the disk is booting, some boot1 loader ist located at
 sector 0 (from the beginning of this slice). How is it assured,
 that the first block will never be overwritten? Where is boot1
 located, where boot2?
 
 Comparing the first sector with boot and boot1 differs already
 at the first char. (and there were no updates so far)
 
 That sector 0 lies outside of the slice block 0. What you are
 seeing is not an absolute disk offset, but the offset in to the slice.  
 
 Right, and sector 0 of the bsd-partition (label) begins where
 the bsd-partition- starts. Since offset of ads1a is zero, sector 0
 ad0s1a is the same as sector 0 of ad0s1.
 
 So my problem was to understand how there can be any room for
 boot1+2, if the filesystem start right there. My fault was to assume,
 that the ufs-superblock begins at first sector. (see below)

The only thing the boot sector does is bring in the boot file which
is in a file on the filesystem.   It doesn't need any special sector
after the label sector.   That label sector also stands outside
the allocatable space.Remember that all addressing is really
virtual, not absolute, even though it looks a little like it is absolute.

For more detailed information, you will have to go to one of the
books on just how the system is built which includes how the disk
blocks and boot sectors are layed out.   I had one, but don't know
just where it is, or I'd include table for a bit of it.

jerry

 
 It is possible to create it otherwise but isn't done that
 way by default.Nowdays, actually a whole track is held
 out, instead of just sector 0 and that is where some of the
 fancier MBRs such as GRUB get their extra space to work.
 But, the standard FreeBSD MBR sticks to the official standard
 of just one sector - which is why it is so plain vanilla.
 
 Since I have no real use for a DOS/MBR-partitiontable, I'd like to
 partitionate a dangerously dedicated layout. How would I do
 this in a safe way?
 
 I found the answer to my question in sys/ufs/ffs/fh.h: UFS leaves
 some sectors free up to the superblock. Dependening on x
 that can be 0k, 8k, 32k, 64k or even 256k.
 
 Adam
 
 -- 
 
 
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Re: bsdlabel offset

2008-03-20 Thread Jerry McAllister
On Thu, Mar 20, 2008 at 04:38:00PM +0100, Adam Pordzik wrote:

 Jerry McAllister wrote:
 On Fri, Mar 14, 2008 at 11:40:55AM +0100, Tektonaut wrote:
 
 Hi,
 
 following bsdllabel output caught my attention:
 
 #sizeoffsetfstype   [fsize bsize bps/cpg]
  a:  2097152 04.2BSD 2048 16384 28552 
  b:  4194304   2097152  swap
  c: 3125766420unused0 0 # raw part, 
  don't edit
  d: 33554432   62914564.2BSD 2048 16384 28552 
 ...
 
 I created this disk with sade or sysinstall. What I'm not sure
 about is that partition 'a' has an offset of 0. With an 8k big
 /boot/boot I would guess offset should be 16block large.
 
 But since the disk is booting, some boot1 loader ist located at
 sector 0 (from the beginning of this slice). How is it assured,
 that the first block will never be overwritten? Where is boot1
 located, where boot2?
 
 Comparing the first sector with boot and boot1 differs already
 at the first char. (and there were no updates so far)
 
 That sector 0 lies outside of the slice block 0. What you are
 seeing is not an absolute disk offset, but the offset in to the slice.  
 
 Right, and sector 0 of the bsd-partition (label) begins where
 the bsd-partition- starts. Since offset of ads1a is zero, sector 0
 ad0s1a is the same as sector 0 of ad0s1.
 
 So my problem was to understand how there can be any room for
 boot1+2, if the filesystem start right there. My fault was to assume,
 that the ufs-superblock begins at first sector. (see below)
 
 It is possible to create it otherwise but isn't done that
 way by default.Nowdays, actually a whole track is held
 out, instead of just sector 0 and that is where some of the
 fancier MBRs such as GRUB get their extra space to work.
 But, the standard FreeBSD MBR sticks to the official standard
 of just one sector - which is why it is so plain vanilla.
 
 Since I have no real use for a DOS/MBR-partitiontable, I'd like to
 partitionate a dangerously dedicated layout. How would I do
 this in a safe way?
 
 I found the answer to my question in sys/ufs/ffs/fh.h: UFS leaves
 some sectors free up to the superblock. Dependening on x
 that can be 0k, 8k, 32k, 64k or even 256k.
 
Yup.

Dangerously dedicated just means skipping making a slice and BSDlabeling
the ad0 or da0 address rather than ad0s1 or da0s1.

It is safe as long as the disk must never be looked at by anything
other than FreeBSD.

jerry

 
 Adam
 
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bsdlabel offset

2008-03-14 Thread Tektonaut

Hi,

following bsdllabel output caught my attention:

#sizeoffsetfstype   [fsize bsize bps/cpg]
 a:  2097152 04.2BSD 2048 16384 28552 
 b:  4194304   2097152  swap
 c: 3125766420unused0 0 # raw part, don't edit
 d: 33554432   62914564.2BSD 2048 16384 28552 
...


I created this disk with sade or sysinstall. What I'm not sure
about is that partition 'a' has an offset of 0. With an 8k big
/boot/boot I would guess offset should be 16block large.

But since the disk is booting, some boot1 loader ist located at
sector 0 (from the beginning of this slice). How is it assured,
that the first block will never be overwritten? Where is boot1
located, where boot2?

Comparing the first sector with boot and boot1 differs already
at the first char. (and there were no updates so far)


Little bemused regards,
Adam

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Re: bsdlabel offset

2008-03-14 Thread Jerry McAllister
On Fri, Mar 14, 2008 at 11:40:55AM +0100, Tektonaut wrote:

 Hi,
 
 following bsdllabel output caught my attention:
 
 #sizeoffsetfstype   [fsize bsize bps/cpg]
  a:  2097152 04.2BSD 2048 16384 28552 
  b:  4194304   2097152  swap
  c: 3125766420unused0 0 # raw part, don't 
  edit
  d: 33554432   62914564.2BSD 2048 16384 28552 
 ...
 
 I created this disk with sade or sysinstall. What I'm not sure
 about is that partition 'a' has an offset of 0. With an 8k big
 /boot/boot I would guess offset should be 16block large.
 
 But since the disk is booting, some boot1 loader ist located at
 sector 0 (from the beginning of this slice). How is it assured,
 that the first block will never be overwritten? Where is boot1
 located, where boot2?
 
 Comparing the first sector with boot and boot1 differs already
 at the first char. (and there were no updates so far)

That sector 0 lies outside of the slice block 0.   What you are
seeing is not an absolute disk offset, but the offset in to the slice.  

It is possible to create it otherwise but isn't done that
way by default.Nowdays, actually a whole track is held
out, instead of just sector 0 and that is where some of the
fancier MBRs such as GRUB get their extra space to work.
But, the standard FreeBSD MBR sticks to the official standard
of just one sector - which is why it is so plain vanilla.

jerry

 
 
 Little bemused regards,
 Adam
 
 -- 
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