export PATH in script called via Cron.

[Paul Halliday]

I have a script that I call via Cron.

It wont work unless I include a path:

#!/usr/local/bin/bash
PATH=/sbin:/bin:/usr/sbin:/usr/bin:/usr/local/bin:/usr/local/sbin
export $PATH

which is fine and works. Out of curiosity though, why is it that if I
call it from the cl like ./test.sh I get this error:

./test.sh: line 3: export:
`/sbin:/bin:/usr/sbin:/usr/bin:/usr/local/bin:/usr/local/sbin': not a
valid identifier

The script still works but it does drop that error.

What does it mean?

Thanks.
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Re: export PATH in script called via Cron.

[krad]

2009/10/16 Paul Halliday paul.halli...@gmail.com

 I have a script that I call via Cron.

 It wont work unless I include a path:

 #!/usr/local/bin/bash
 PATH=/sbin:/bin:/usr/sbin:/usr/bin:/usr/local/bin:/usr/local/sbin
 export $PATH

 which is fine and works. Out of curiosity though, why is it that if I
 call it from the cl like ./test.sh I get this error:

 ./test.sh: line 3: export:
 `/sbin:/bin:/usr/sbin:/usr/bin:/usr/local/bin:/usr/local/sbin': not a
 valid identifier

 The script still works but it does drop that error.

 What does it mean?

 Thanks.
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 freebsd-questions-unsubscr...@freebsd.org


drop the $ in front of path in the export line
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