Re: ot: regular expression help

2009-07-07 Thread Matthew Seaman

Aryeh M. Friedman wrote:
I am attempting to make (without the perl expansions) a regular 
expansion that when used as a delim will split words on any 
punction/whitespace character *EXCEPT* "$" (for java people I want to 
feed it into something like this:


for(String foo:input.split([insert regex here])
   ...


Well, there's no way to say "all foo except bar" using standard regexes, so
you can't use the [:punct:] character class. You'll have to roll your own
class.

If your input is ASCII then see ispunct(3) for a handy list of all the
ascii punctuation characters.  I guess you'll need a RE something like this:

  []!"#%&'\(\)\*\+,\./:;<=>?...@[\\^_`{\|}~-[:space:]]+

although that's completely untried, quite likely to not have all the
metacharacters properly escaped (exactly what is or isn't a metacharacter
depends on the RE implementation you're using) and is probably horribly
confused due to the inclusion of '[' '-' and ']' amongst the characters
matched in the range.  


If you're using anything other than ascii, then I suspect you're going
to have problems with RE libs anyhow, unless you can somehow use PCRE.  
The \p{isPunct} and \p{isWhite} escapes for matching unicode punctuation

or whitespace is probably what you need.

Even so, your best choice would probably be to separately check strings
for the presence of $ characters -- maybe transform those $ characters to
something else -- and then split on any remaining punctuation characters.

Cheers,

Matthew

--
Dr Matthew J Seaman MA, D.Phil.   7 Priory Courtyard
 Flat 3
PGP: http://www.infracaninophile.co.uk/pgpkey Ramsgate
 Kent, CT11 9PW



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Re: ot: regular expression help

2009-07-07 Thread Steve Bertrand
Aryeh M. Friedman wrote:
> I am attempting to make (without the perl expansions) a regular
> expansion that when used as a delim will split words on any
> punction/whitespace character *EXCEPT* "$" (for java people I want to
> feed it into something like this:
> 
> for(String foo:input.split([insert regex here])

Since regexs are generally portable, here is a Perl version that splits
on any non alpha-num including spaces, but disregards the '$'. (regex
between / and /. Even though you said no Perl, I did it anyway ;)

my $string = 'hello%wo$rld*ste ve';

print join (', ', (split(/[^\w\$]/, $string)));

...output:

hello, wo$rld, ste, ve

Steve




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