Re: shell command line argument + parsing function
2009/8/31 Stefan Miklosovic miklosovic.free...@gmail.com:
hi,
assuming I execute shell script like this
$ ./script -c hello world
I want to save hello world string to variable COMMENT in shell script.
code:
#!/bin/sh
parse_cmdline() {
while [ $# -gt 0 ]; do
case $1 in
-c)
shift
COMMENT=$1
;;
esac
shift
done
}
parse_cmdline $*
echo $COMMENT
exit 0
How about getopts builtin, so you can use:
./script -c hello world or
./script -chello world or
while getopts c: f; do
case $f in
c)
COMMENT=$OPTARG
;;
\?)
echo 'usage: $0 [-c string]'
exit 1
;;
esac
done
echo COMMENT: $COMMENT
--
Artis Caune
Everything should be made as simple as possible, but not simpler.
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Re: shell command line argument + parsing function
On Mon, Aug 31, 2009, Stefan Miklosovic wrote:
hi,
assuming I execute shell script like this
$ ./script -c hello world
I want to save hello world string to variable COMMENT in shell script.
code:
#!/bin/sh
parse_cmdline() {
while [ $# -gt 0 ]; do
case $1 in
-c)
shift
COMMENT=$1
;;
esac
shift
done
}
parse_cmdline $*
echo $COMMENT
exit 0
but that only write out hello. I tried to change $* to $@, nothing
changed.
Did you put $@ in quotes? That is parse_cmdline $@. I haven't
tried this in calling functions in scripts, but use it frequently
when calling scripts from other scripts. I would probably use
something like:
for arg in $@; do
dosomething $arg
done
Bill
--
INTERNET: b...@celestial.com Bill Campbell; Celestial Software LLC
URL: http://www.celestial.com/ PO Box 820; 6641 E. Mercer Way
Voice: (206) 236-1676 Mercer Island, WA 98040-0820
Fax:(206) 232-9186 Skype: jwccsllc (206) 855-5792
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-- John C. Dvorak
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Re: shell command line argument + parsing function
hehe :D
easy as hell, one has to enclose argument of parse_cmdline into brackets :)
parse_cmdline $@
sorry for noise
On Mon, Aug 31, 2009 at 1:07 AM, Stefan Miklosovic
miklosovic.free...@gmail.com wrote:
hi,
assuming I execute shell script like this
$ ./script -c hello world
I want to save hello world string to variable COMMENT in shell script.
code:
#!/bin/sh
parse_cmdline() {
while [ $# -gt 0 ]; do
case $1 in
-c)
shift
COMMENT=$1
;;
esac
shift
done
}
parse_cmdline $*
echo $COMMENT
exit 0
but that only write out hello. I tried to change $* to $@, nothing
changed.
It is interesting, that if I dont put while loop into function
parse_cmdline,
and do echo $COMMENT, it writes hello world.
I WANT that function style. How to do it ?
thank you
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Re: shell command line argument + parsing function
On Mon, Aug 31, 2009 at 01:07:36AM +0200, Stefan Miklosovic wrote:
hi,
assuming I execute shell script like this
$ ./script -c hello world
I want to save hello world string to variable COMMENT in shell script.
code:
#!/bin/sh
parse_cmdline() {
while [ $# -gt 0 ]; do
case $1 in
-c)
shift
COMMENT=$1
;;
esac
shift
done
}
parse_cmdline $*
echo $COMMENT
exit 0
but that only write out hello. I tried to change $* to $@, nothing
changed.
But if you use $@ (with the quote marks) instead it should work fine.
For further explanation please read the sh(1) man page where it explains the
special parameters $* and $@, while paying special attention to how they
expand when used within double-quotes.
It is interesting, that if I dont put while loop into function
parse_cmdline,
and do echo $COMMENT, it writes hello world.
I WANT that function style. How to do it ?
thank you
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--
Insert your favourite quote here.
Erik Trulsson
ertr1...@student.uu.se
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