On Tuesday 09 January 2007 06:10, Greg Albrecht wrote:
while searching for 'freebsd process states' on google i came across
this thread:
http://lists.freebsd.org/pipermail/freebsd-questions/2006-December/138024.h
tml i'm a new subscriber, so i can't reply to the original thread.
i'm guessing [EMAIL PROTECTED]'s original question was something more
like: that do the values in the STATE column in top mean? here's an
example of what i'm talking about:
## bad 'top' formatting to come
PID USERNAME PRI NICE SIZERES STATE C TIME WCPUCPU
COMMAND 95698 mysql 200 388M 349M kserel 0 266.7H 0.63%
0.63% mysqld 98237 jffnms 80 21224K 14412K nanslp 0 0:02
0.59% 0.59% php 98239 jffnms 960 22124K 15292K select 1 0:02
0.49% 0.49% php 98596 root 960 4124K 2560K CPU1 1
0:00 0.51% 0.05% top 1263 root40 1408K 708K accept 0
0:07 0.00% 0.00% vsftpd 3405 galbrecht 80 4876K 2676K wait
0 0:00 0.00% 0.00% bash 94414 root40 3284K 1968K
sbwait 1 0:00 0.00% 0.00% mysql ## end of bad formatting
this snippet of top shows the following values for STATE: kserel,
nanslp, select, CPU1, accept, wait, sbwait
this thread has already cleared up these states:
nanslp: Waiting for 1 second. [EMAIL PROTECTED]
select: Waiting for a select() to complete [EMAIL PROTECTED]
wait: Waiting for something to happen, possibly time limited (= 1
second) [EMAIL PROTECTED]
top(1) tells us: STATE is the current state (one of sleep, WAIT,
run, idl, zomb, or stop)
eh, not so much.
man clears up some of these states:
sleep: The sleep command suspends execution for a minimum of
seconds. - sleep(1)
accept: accept a connection on a socket - accept(2)
i bet i can answer with:
run: process is running?
zomb: zombie process, terminated but not removed from memory
that leaves us with:
kserel?
The process is waiting for some event to occur in one of its threads.
see kse(2). Please someone correct me if I'm wrong.
sbwait?
Wait for data to arrive at/drain from a socket buffer. (see
sys/kern/uipc_socket2.c:363). So, it is essentially waiting for network I/O.
idl?
stop?
I've never seen a process in one of these states.
does the previous answer still apply (ask the developers of those
programs)?
The states are set in the kernel, so the (userland) program developers
wouldn't be able to answer these questions.
Hope this helps,
Pieter
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