On Wed, Aug 24, 2022 at 09:42:54AM +0200, Ralf Hemmecke wrote:
>
> A recurrence for the primes is of course a dream, but why does guess gives
> me something for
>
> guess([2,3,5,7,11,13])
>
> and
>
> guess([2,3,5,7,11,13,17,19])
>
> but returns the empty list for guess([2,3,5,7,11,13,17])?
On 24.08.2022 09:42, Ralf Hemmecke wrote:
>> The reason that the innermost terms (i.e., the factors in the product
>
> Still there is the question, how am I supposed to take the result apart for
> further computation. That should be explained somewhere. You cannot expect
> your
> users to
On Wed, Aug 24, 2022 at 09:42:54AM +0200, Ralf Hemmecke wrote:
>
> Still there is the question, how am I supposed to take the result apart for
> further computation. That should be explained somewhere. You cannot expect
> your users to know how the internals of Expression(Integer) are to be
>
I do not know how to take the result apart for further computations. What
you can do is "eval(result, n=17)". Also, there is "getEq$RECOP" which
gives you the equation of a recurrence.
The result is obtained by taking quotients and differences and then
applying interpolation to the resulting
The reason that the innermost terms (i.e., the factors in the product
indexed by p_5 in your output) are given as a recurrence rather than the
seemingly equivalent function f(p_5) = 1 is that they are in fact not
equivalent.
Yes, I understand this recurrence aspect.
The recurrence (p - 1)
The reason that the innermost terms (i.e., the factors in the product
indexed by p_5 in your output) are given as a recurrence rather than the
seemingly equivalent function f(p_5) = 1 is that they are in fact not
equivalent.
The recurrence (p - 1) f(p) + p - 1 = 0 is satisfied also by f(0) =
BTW, QuickLaTeX may be more convenient than a real TeX installation
for cases like these:
https://quicklatex.com
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On Tue, 23 Aug 2022 at 16:26, Ralf Hemmecke wrote:
>
> Martin, Waldek,
>
> can you tell me how I am supposed to interpret the result of this:
>
> (153) -> guess([2,3,5,7,11,13,17,19])
>
> (153)
> [
> s - 1 p - 1s - 1
> n - 18 7 6
>
OK the part inside the [] brackets should be interpreted as (let me
solve that equation): f(p5)=(1-p5)/(p5-1). So except for p5=1 f(p5)=-1
and can be anything if p5=1. Hmmm... Does that make sense? f(1) arbitrary?
I think the guessing package must improve on the output. Have you seen
that
On Tue, Aug 23, 2022 at 04:26:02PM +0200, Ralf Hemmecke wrote:
> Martin, Waldek,
>
> can you tell me how I am supposed to interpret the result of this:
>
> (153) -> guess([2,3,5,7,11,13,17,19])
>
>(153)
>[
>s - 1 p - 1s - 1
>n - 18 7 6
>
Martin, Waldek,
can you tell me how I am supposed to interpret the result of this:
(153) -> guess([2,3,5,7,11,13,17,19])
(153)
[
s - 1 p - 1s - 1
n - 18 7 6
--+++-++--+ ++-++
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