You may be in luck, and it may do precisely what you want, but by the
time you made sure it does, you've already wasted far too much time on
it. Here is an example that mosty likely *not* do what you want:
$i = 20;
my($x, $y, $z) = ($i++, $i, $i++);
This is a great example, as
$i = 20;
my($x, $y, $z) = ($i++, +$i, $i++);
Here is a good addition to Bart's examples:
my $i = 20;
my ($x, $y, $z) = ($i++, -$i, $i++);
print $x $y $z\n;
Understanding the other examples... can you guess what does it prints?
And the problem persists even if you make the
On Mon, 25 Nov 2002 11:34:23 + (GMT), [EMAIL PROTECTED] wrote:
$i = 20;
my($x, $y, $z) = ($i++, $i, $i++);
Now, it appears that perl's evaluation order is accident rather than
design - so you SHOULD NOT rely on it. Avoid causing side-effects on
variables you use more than once...
