Hi Todd, Can you just pass in “.”?
<command interpreter="python"> the_tool.py -o ‘.' Thanks for using Galaxy, Dan On Dec 11, 2015, at 4:00 PM, Todd Oakley <todd.oak...@lifesci.ucsb.edu> wrote: > Greetings, > I feel this must be simple, but I cannot find it. > > I'm making a wrapper for a tool that requires the output directory to be > specified on the command line of a python script (otherwise it uses the path > of the input file for the multiple output files). How can I pass the working > directory to the tool from the xml file? > > <command interpreter="python"> > the_tool.py -o $DIRECTORY_WHERE_GALAXY_RUNS_THE_TOOL > > This is similar to from_work_dir in the outputs -- but I need the path of > the directory that does not include any file names. > > > Thanks! > > Todd Oakley, UCSB > ___________________________________________________________ > Please keep all replies on the list by using "reply all" > in your mail client. To manage your subscriptions to this > and other Galaxy lists, please use the interface at: > https://lists.galaxyproject.org/ > > To search Galaxy mailing lists use the unified search at: > http://galaxyproject.org/search/mailinglists/ ___________________________________________________________ Please keep all replies on the list by using "reply all" in your mail client. To manage your subscriptions to this and other Galaxy lists, please use the interface at: https://lists.galaxyproject.org/ To search Galaxy mailing lists use the unified search at: http://galaxyproject.org/search/mailinglists/
