On 22/03/2014 20:16, Bob Brand wrote:
Hello Duncan,
In message <bug-250...@http.www.riscos.info/bugzilla3/> you wrote:
printf("%f\n",sqrt(2.0));
Looks like you have fallen in a classic C pitfall:
passing a double argument to a vararg/stdarg function
but interpreting it as float.
No, "%f" is a correct format specifier for double.
The same wrong output is given with C++ iostreams, where there's no
format specifier:
#include <iostream>
#include <cmath>
int main(void) {
std::cout << sqrt(2.0) << std::endl;
return 0;
}
*g++ sqrt.cc
*a/out
1.4375
Regards, Duncan
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