https://gcc.gnu.org/bugzilla/show_bug.cgi?id=112101
--- Comment #2 from Abdulmalek Almkainzi ---
Another correction, I'm sorry, its a bit hard to write hypothetical code.
the macro print_func:
#define print_func(f) \
printf( \
_Generic( (__typeof_arg(f, 0)){0}, \
int: #f "(int)", \
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=112101
--- Comment #1 from Abdulmalek Almkainzi ---
correction for the gurantee_type macro:
#define gurantee_type(exp, type) \
_Generic(exp, type: exp, default: (type){0})
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=112101
Bug ID: 112101
Summary: feature request: typeof_arg for extracting the type of
a function's (or function pointer's) arguments
Product: gcc
Version: unknown
Status:
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=111421
--- Comment #3 from Abdulmalek Almkainzi ---
(In reply to jos...@codesourcery.com from comment #1)
> See the definitions of "named constant" and "compound literal constant".
> Array element accesses aren't allowed, and the example you have
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=111421
Bug ID: 111421
Summary: constexpr not working with array subscript
Product: gcc
Version: 13.2.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c
