------- Comment #1 from pinskia at gcc dot gnu dot org  2008-08-03 20:32 -------
That is correct.  % is not really the modulo operator but instead the remainder
operator :).  So (-a) %b is the same as -(a%b).


-- 

pinskia at gcc dot gnu dot org changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|                            |INVALID


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=37015

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