https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66917
Ramana Radhakrishnan ramana at gcc dot gnu.org changed:
What|Removed |Added
Keywords|
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66917
Richard Biener rguenth at gcc dot gnu.org changed:
What|Removed |Added
CC||rguenth at
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66917
--- Comment #7 from ktkachov at gcc dot gnu.org ---
(In reply to Richard Biener from comment #6)
Probably because you access a.u/b.u which is uint64_t and thus the union
is laid out as having 8 byte alignment?
How do the original GENERIC
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66917
--- Comment #8 from ktkachov at gcc dot gnu.org ---
The 007t.lower one looks like:
try
{
MEM[(char * {ref-all})a] = MEM[(char * {ref-all})ap];
MEM[(char * {ref-all})b] = MEM[(char * {ref-all})bp];
D.5587 = a.u[0];
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66917
--- Comment #5 from ktkachov at gcc dot gnu.org ---
The slp2 dump at tree level says about the ap pointer:
base_address: ap_2(D)
offset from base address: 0
constant offset from base address: 0
step: 0
