http://gcc.gnu.org/bugzilla/show_bug.cgi?id=55931
Bug #: 55931 Summary: Constexpr member function inside a static member is not working Classification: Unclassified Product: gcc Version: 4.7.2 Status: UNCONFIRMED Severity: major Priority: P3 Component: c++ AssignedTo: unassig...@gcc.gnu.org ReportedBy: vince....@gmail.com The call of a constexpr member of a class into a static member of the same class is not working. This is illustrated by the following code: (tested on g++ 4.7.1 and 4.7.2, but it may also affect g++ 4.8) ------------------------------------------------------------------- #include <iostream> #include <type_traits> template<typename Type> class Test { public: constexpr Test(const Type val) : _value(val) {} constexpr Type get() const {return _value;} static void test() { static constexpr Test<int> x(42); std::integral_constant<int, x.get()> i; // This is not working std::cout<<i<<std::endl; } protected: Type _value; }; int main(int argc, char *argv[]) { static constexpr Test<int> x(42); std::integral_constant<int, x.get()> i; // This is working std::cout<<i<<std::endl; Test<double>::test(); return 0; } ------------------------------------------------------------------- which produces the following error: ------------------------------------------------------------------- main.cpp: In static member function ‘static void Test<Type>::test()’: main.cpp:13:48: erreur: invalid use of ‘Test<Type>::get<int>’ to form a pointer-to-member-function main.cpp:13:48: note: a qualified-id is required main.cpp:13:48: erreur: could not convert template argument ‘x.Test<Type>::get<int>()’ to ‘int’ main.cpp:13:51: erreur: invalid type in declaration before ‘;’ token -------------------------------------------------------------------