http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #1 from Andrew Pinski pinskia at gcc dot gnu.org ---
This is documented to do this even in 4.8
(http://gcc.gnu.org/onlinedocs/gcc-4.8.2/gcc/Warning-Options.html):
In C++ enumeral mismatches in conditional expressions are also
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #2 from Paul Pluzhnikov ppluzhnikov at google dot com ---
(In reply to Andrew Pinski from comment #1)
This is documented to do this even in 4.8
(http://gcc.gnu.org/onlinedocs/gcc-4.8.2/gcc/Warning-Options.html):
In C++ enumeral
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
Manuel López-Ibáñez manu at gcc dot gnu.org changed:
What|Removed |Added
CC||manu at gcc
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #4 from Manuel López-Ibáñez manu at gcc dot gnu.org ---
(In reply to Manuel López-Ibáñez from comment #3)
I don't even understand what this code is trying to warn about:
if (TREE_CODE (arg2_type) == ENUMERAL_TYPE
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #5 from Manuel López-Ibáñez manu at gcc dot gnu.org ---
I think it should not warn for anonymous enums. The point of the warning is
that using different enum types in a conditional expression is often some
programming mistake. But in
