https://gcc.gnu.org/bugzilla/show_bug.cgi?id=86082
Bug ID: 86082
Summary: user-defined literals are not converted to the
execution charset
Product: gcc
Version: 8.0.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: krebbel at gcc dot gnu.org
Target Milestone: ---
template <char... p> void q();
template <> void q<'1','2','3'>() {}
template <char... p> void operator""_test() { q<p...> (); }
int
main ()
{
123_test;
}
builds fine with 'g++ t.cpp'
but triggers a link error compiled with 'g++ t.cpp -fexec-charset=IBM1047'
In the specialization of q the string literals '1', '2', '3' get converted to
the target character set as expected. However, the call generated in the body
of the operator does still use the source character set:
10: 0000000000000000 2 FUNC GLOBAL DEFAULT 2 void q<(char)-15,
(char)-14, (char)-13>()
11: 0000000000000002 16 FUNC GLOBAL DEFAULT 2 main
12: 0000000000000000 12 FUNC WEAK DEFAULT 6 void operator""
_test<(char)49, (char)50, (char)51>()
13: 0000000000000000 0 NOTYPE GLOBAL DEFAULT UND void q<(char)49,
(char)50, (char)51>()
When converting a user-defined literal into string literals also a conversion
into the execution charset is required.
