https://gcc.gnu.org/bugzilla/show_bug.cgi?id=87989
Bug ID: 87989
Summary: Calling operator T() invokes wrong conversion operator
overload
Product: gcc
Version: 9.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: kretz at kde dot org
Target Milestone: ---
Testcase (https://godbolt.org/z/sStNGV):
struct X {
template <class T> operator T() const;
operator float() const;
};
template <class T>
T f(const X &x) { return x.operator T(); }
template float f<float>(const X &);
Starting with GCC8, this calls `X::operator float<float>() const` instead of
`X::operator float() const`. The behavior is correct if function f is changed
to `{ return x; }`; i.e. implicit call of the conversion operator.
I have not double-checked the standard, but clang, EDG, MSVC and GCC <= 7 do
not show this behavior.
