namespace S
{
int f ()
{
int i = 42;
{
extern int i;
return i;
}
}
}
generates DWARF:
# Grossly simplified.
<1><2d>: Abbrev Number: 2 (DW_TAG_namespace)
<2e> DW_AT_name : S
<2><36>: Abbrev Number: 3 (DW_TAG_subprogram)
<37> DW_AT_external : 1
<38> DW_AT_name : f
<3c> DW_AT_MIPS_linkage_name: (indirect string, offset: 0x49): _ZN1S1fEv
<61> DW_AT_low_pc : 0x0
<69> DW_AT_high_pc : 0x13
<71> DW_AT_frame_base : 0x0 (location list)
<3><75>: Abbrev Number: 7 (DW_TAG_lexical_block)
<76> DW_AT_low_pc : 0x4
<7e> DW_AT_high_pc : 0x11
<4><86>: Abbrev Number: 8 (DW_TAG_variable)
<87> DW_AT_name : i
<8f> DW_AT_location : 2 byte block: 91 6c (DW_OP_fbreg: -20)
<4><92>: Abbrev Number: 9 (DW_TAG_lexical_block)
<93> DW_AT_low_pc : 0xb
<9b> DW_AT_high_pc : 0x11
<2><45>: Abbrev Number: 4 (DW_TAG_variable)
<46> DW_AT_name : i
<4a> DW_AT_MIPS_linkage_name: (indirect string, offset: 0x40): _ZN1S1iE
<52> DW_AT_external : 1
<53> DW_AT_declaration : 1
But the last DIE should have been <5><45> being in inner DW_TAG_lexical_block
so that debugger would display external variable S::i in the inner block.
(I have inlined the DW_AT_specification reference in the dump above.)
Similar case in C works OK:
int
f (void)
{
int i = 42;
{
extern int i;
return i;
}
}
--
Summary: C++ external inner reference does not override outer
scope
Product: gcc
Version: 4.5.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: debug
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: jan dot kratochvil at redhat dot com
GCC target triplet: x86_64-unknown-linux-gnu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=43325
