On Sat, 11 Nov 2023 at 23:00, Cassio Neri wrote:
>
> The current implementation returns
> (_M_y & (__is_multiple_of_100 ? 15 : 3)) == 0;
> where __is_multiple_of_100 is calculated using an obfuscated algorithm which
> saves one ror instruction when compared to _M_y % 100 == 0 [1].
>
> In leap
The current implementation returns
(_M_y & (__is_multiple_of_100 ? 15 : 3)) == 0;
where __is_multiple_of_100 is calculated using an obfuscated algorithm which
saves one ror instruction when compared to _M_y % 100 == 0 [1].
In leap years calculation, it's correct to replace the divisibility
