Committed as obvious (once the problem is identified). When simplification of an expression occurs, parenthesis can be inserted. When simplifying a constant expression, need to check for inserted parenthesis.
2019-09-11 Steven G. Kargl <ka...@gcc.gnu.org> PR fortran/91553 * simplify.c (gfc_convert_constant): During conversion check if the constant is enclosed in parenthesis, and simplify expression. 2019-09-11 Steven G. Kargl <ka...@gcc.gnu.org> PR fortran/91553 * gfortran.dg/pr91553.f90: New test. -- Steve
Index: gcc/fortran/simplify.c =================================================================== --- gcc/fortran/simplify.c (revision 275651) +++ gcc/fortran/simplify.c (working copy) @@ -8503,6 +8503,12 @@ gfc_convert_constant (gfc_expr *e, bt type, int kind) { if (c->expr->expr_type == EXPR_ARRAY) tmp = gfc_convert_constant (c->expr, type, kind); + else if (c->expr->expr_type == EXPR_OP + && c->expr->value.op.op == INTRINSIC_PARENTHESES) + { + gfc_simplify_expr (c->expr, 1); + tmp = f (c->expr, kind); + } else tmp = f (c->expr, kind); } Index: gcc/testsuite/gfortran.dg/pr91553.f90 =================================================================== --- gcc/testsuite/gfortran.dg/pr91553.f90 (nonexistent) +++ gcc/testsuite/gfortran.dg/pr91553.f90 (working copy) @@ -0,0 +1,9 @@ +! { dg-do run } +! Code contributed by Gerhard Steinmetz +program p + complex z(1) + z = (1.0, 2.0) * [real :: (3.0 + 4.0)] + if (real(z(1)) /= 7.) stop 1 + if (aimag(z(1)) /= 14.) stop 2 +end