On 08/10/06, Ow Mun Heng <[EMAIL PROTECTED]> wrote:
Does anyone know how to go about escaping a "*" in a bash script?
I want to do the following
query=" select * from table where column1='something' "
Well one you can use different quotes:
query='select * from table'
Or you can \* it.
quer
On Sun, 2006-10-08 at 18:13 +0800, Ow Mun Heng wrote:
> Does anyone know how to go about escaping a "*" in a bash script?
>
> I want to do the following
>
> query=" select * from table where column1='something' "
>
nevermind..
I did it like this
query=" select \" *\" from table where col
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Ow Mun Heng wrote:
> Does anyone know how to go about escaping a "*" in a bash script?
>
> I want to do the following
>
> query=" select * from table where column1='something' "
>
>
As you use the "" it is still a * in the $query, but you have
Does anyone know how to go about escaping a "*" in a bash script?
I want to do the following
query=" select * from table where column1='something' "
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