I'm mostly the same way myself. The data was provided to me in a CSV
file which made me think about spreadsheets. I really didn't expect to
get an answer when I wrote the Open Office user's list but the
response I got was very detailed and probably took me less time to do
implement what I asked abo
On Fri, 2007-11-16 at 05:28 -0800, Mark Knecht wrote:
> Thanks for all the answers. They were interesting.
Actually your answer was the most interesting. As a programmer, I'm
always looking for a programmatic way of solving such problems. I would
have never thought of using a spreadsheet (I onl
On Nov 15, 2007 5:58 PM, Philip Webb <[EMAIL PROTECTED]> wrote:
> 071115 Mark Knecht wrote:
> > I have a data file with data that changes infrequently.
> > The file lists only the day the data changes.
> > There are only 144 lines representing 23 years of data.
> > There are three values for the da
071115 Mark Knecht wrote:
> I have a data file with data that changes infrequently.
> The file lists only the day the data changes.
> There are only 144 lines representing 23 years of data.
> There are three values for the data - 1, 0 & -1. The file looks like this:
> 09/27/74, 1
> 07/11/75,
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA512
I'd read the whole file into a 2-field array, then just fill-in the gaps until
the next value-change
(value being the 2nd column).
- --
Arturo "Buanzo" Busleiman - Consultor Independiente en Seguridad Informatica
Apoye la Musica Libre - Vote Futura
I'd use something like perl[1] to read (2 lines initially) and then each
line of the original file, generate the intermediate lines by comparing
each line to the one before... printing the new generated lines to
stdout (or a specified file if desired).
Cheers
Mark
[1], perl, php, python, awk
Hi,
I know this is EXTREMELY off topic but I don't know of another
better list to ask on. I'm hoping maybe there is a Linux command line
method for doing this. Thanks in advance.
I have a data file with data that changes infrequently. The file
lists only the day the data changes. There are o
On Thu, 2007-11-15 at 14:25 -0800, Mark Knecht wrote:
> Hi,
>I know this is EXTREMELY off topic but I don't know of another
> better list to ask on. I'm hoping maybe there is a Linux command line
> method for doing this. Thanks in advance.
>
>I have a data file with data that changes infr
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