Re: [gentoo-user] sed/awk question

Pandu Poluan pa...@poluan.info wrote: On Tue, Nov 22, 2011 at 10:26, Adam Carter adamcart...@gmail.com wrote: sed -r -e 's/(.*)-[0-9].*/\1/' You know, that looks familiar... are you trying to get a package name from the list of eix-installed? :-) No - its non-gentoo. In this case it

Re: [gentoo-user] sed/awk question

On Tue, Nov 22, 2011 at 16:40, Joerg Schilling joerg.schill...@fokus.fraunhofer.de wrote: Pandu Poluan pa...@poluan.info wrote: On Tue, Nov 22, 2011 at 10:26, Adam Carter adamcart...@gmail.com wrote: sed -r -e 's/(.*)-[0-9].*/\1/' You know, that looks familiar... are you trying to get a

Re: [gentoo-user] sed/awk question

On 11/22/2011 10:40 AM, Joerg Schilling wrote: Here's an alternative: sed -r -e 's/-[0-9].*//' Nust a note: sed has no option -r and 's/(.*)-[0-9].*/\1/' is a garbled command. A corrected version would be 's/\(.*\)-[0-9].*/\1/' So the main question is: why do you use a non-existing

Re: [gentoo-user] sed/awk question

Pandu Poluan pa...@poluan.info wrote: sed -r -e 's/-[0-9].*//' Nust a note: sed has no option -r and 's/(.*)-[0-9].*/\1/' is a garbled command. A corrected version would be 's/\(.*\)-[0-9].*/\1/' So the main question is: why do you use a non-existing option? # sed --help Usage:

[gentoo-user] sed/awk question

Hi All, I need to cut a string, which happens to be a filename, using the first dash that's followed by a numeral, so cut -f 1 -d- fails if the filename has an extra dash. How do i do this?

Re: [gentoo-user] sed/awk question

sed -r -e 's/(.*)-[0-9].*/\1/' You know, that looks familiar... are you trying to get a package name from the list of eix-installed? :-) No - its non-gentoo. In this case it hasn't worked $ echo net-snmp-5.3.2.2-5.cp843034001.i386.rpm | sed -r -e 's/(.*)-[0-9].*/\1/' net-snmp-5.3.2.2

Re: [gentoo-user] sed/awk question

I'd use sed and the regex -[0-9] to delimit the field foo=`echo '123--bad-2xyz-3--' | sed -r -e s/-[0-9].*//` echo $foo 123--bad Helpful? Adam Carter wrote: Hi All, I need to cut a string, which happens to be a filename, using the first dash that's followed by a numeral, so cut -f 1 -d-

Re: [gentoo-user] sed/awk question

Oh, and you can get the other end next by foo2=`echo '123--bad-2xyz-3--' | sed -r -e s/$foo//` echo $foo2 -2xyz-3-- Joseph Davis wrote: I'd use sed and the regex -[0-9] to delimit the field foo=`echo '123--bad-2xyz-3--' | sed -r -e s/-[0-9].*//` echo $foo 123--bad Helpful? Adam Carter

Re: [gentoo-user] sed/awk question

On 11/21/2011 06:52 PM, Adam Carter wrote: Hi All, I need to cut a string, which happens to be a filename, using the first dash that's followed by a numeral, so cut -f 1 -d- fails if the filename has an extra dash. How do i do this? Here's a Bourne parameter expansion: blee@eclipse ~ $

Re: [gentoo-user] sed/awk question

I'd use sed and the regex -[0-9] to delimit the field foo=`echo '123--bad-2xyz-3--' | sed -r -e s/-[0-9].*//` echo $foo 123--bad Helpful? Perfect - thanks!

Re: [gentoo-user] sed/awk question

On Tue, Nov 22, 2011 at 10:26, Adam Carter adamcart...@gmail.com wrote: sed -r -e 's/(.*)-[0-9].*/\1/' You know, that looks familiar... are you trying to get a package name from the list of eix-installed? :-) No - its non-gentoo. In this case it hasn't worked $ echo