Thanks for that, Dave. Correction: If Caldeira
and Hoffert are right, that's 7x10^6 x 10^5 tons
of glacier melted per day. ;-)
- G
Ad in Life magazine 1962.
Dave (cc Ken and list):
Thanks to Dave.
1. Since I doubt very much that the computation shown included
anything on CO2 effects, I hope Ken can weigh in on this, per the
discussion last week re:
http://climateprogress.org/wp-content/uploads/2009/11/Warming-burning-091018.pdf
2.
1 digit calculations just for orders of magnitude:
If we assume a doubling of CO2 is 4 W / m2 and the earth is 5 x 10^14 m2, a
doubling of CO2 traps about 2 x 10^15 W.
If we assume 2 GtC / ppm, and think it takes say 300 ppm to double CO2, that
is 600 GtC, 600 x 10^12 kgC = 6 * 10^14 GC, so each
Actually, my calculations some years ago indicated that the ratio for one
year was roughly 1--what gives the high ratio is the long persistence of the
CO2 perturbation.
Mike
On 11/19/09 6:08 PM, Ron Larson rongretlar...@comcast.net wrote:
Dave (cc Ken and list):
Thanks to Dave.
1.
Hi Ken,
Thanks very much for that. I'm particularly interested in your
parenthetic comment at the end:
"(I think that 75 was the ratio of current atmospheric CO2 radiative
forcing to direct heating from fossil fuel burning, but I would need to
go back to check.)"
I had been wondering about
