Re: [Gimp-developer] stdout from lisp

2006-04-10 Thread Kovacs Baldvin
On Sun, Apr 09, 2006 at 09:34 -0700, [EMAIL PROTECTED] wrote:
 Kovacs,
 
 Output from Script-fu can be sent to stdout by first performing a:
 
   (gimp-message-set-handler 1)
 
 and then sending your strings using something like
 
   (gimp-message foobar)
 
 where foobar is the string to printed on stdout.
 
 Perhaps this will be sufficient for your needs?

Yes, definitely! Thank you very much!

(P.s.: as a keep it stupid and simple fan I'd probably arrange things
in a way that the default print methods of siod do print to stdout. But
anyways, what I really needed is just any method to print, so I'll do
with what you showed.).

Thanks,
Baldvin
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Re: [Gimp-developer] stdout from lisp

2006-04-10 Thread Kevin Cozens

[EMAIL PROTECTED] wrote:

Output from Script-fu can be sent to stdout by first performing a:

  (gimp-message-set-handler 1)


The Procedure Browser shows that the arguments '1' has an equivalent (C style) 
name of GIMP_CONSOLE. In Script-Fu you remove the leading GIMP_ from named 
constants shown in the Procedure Browser and change any remaining _ to -. That 
would mean you could use


(gimp-message-set-handler CONSOLE)

which has the extra benefit of being more readable. You don't have to go back 
to the procedure browser to find out what the 1 means.


Just a suggestion to use the named constants where available to make the 
scripts a little more readable, save some trips back to the procedure browser 
which should make any needed debugging a little less tedious.


--
Cheers!

Kevin.

http://www.interlog.com/~kcozens/ |What are we going to do today, Borg?
Owner of Elecraft K2 #2172|Same thing we always do, Pinkutus:
  |  Try to assimilate the world!
#include disclaimer/favourite   |  -Pinkutus  the Borg
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