When showing merges in git-log, the same commit is shown once for each
parent. Combined with "--graph" this results in graph_show_commit()
being called once for each parent without graph_update() being called.
Currently graph_show_commit() does not print anything on subsequent
invocations for the same commit (this was changed by commit 656197a -
"graph.c: infinite loop in git whatchanged --graph -m" from the previous
behaviour of looping infinitely).
Change this so that if the graph code believes it has already shown the
commit it prints a single padding line.
Signed-off-by: John Keeping <j...@keeping.me.uk>
---
graph.c | 10 ++++++++++
1 file changed, 10 insertions(+)
diff --git a/graph.c b/graph.c
index 391a712..2a3fc5c 100644
--- a/graph.c
+++ b/graph.c
@@ -1227,6 +1227,16 @@ void graph_show_commit(struct git_graph *graph)
if (!graph)
return;
+ /*
+ * When showing a diff of a merge against each of its parents, we
+ * are called once for each parent without graph_update having been
+ * called. In this case, simply output a single padding line.
+ */
+ if (graph_is_commit_finished(graph)) {
+ graph_show_padding(graph);
+ shown_commit_line = 1;
+ }
+
while (!shown_commit_line && !graph_is_commit_finished(graph)) {
shown_commit_line = graph_next_line(graph, &msgbuf);
fwrite(msgbuf.buf, sizeof(char), msgbuf.len, stdout);
--
1.8.1.2
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