Re: [go-nuts] Re: golang tour - floating point numbers

2017-04-17 Thread ksampath 
thanks all.. end of the day simple silly one .. went unnoticed ..

On Sunday, April 16, 2017 at 11:53:11 PM UTC+5:30, Janne Snabb wrote:
>
> It does not do this. 
>
> It would be nice in most cases if it did. 
>
> But some times extra parenthesis are useful for making some formula 
> easier to read. 
>
>
> Janne Snabb 
> sn...@epipe.com  
>
> On 2017-04-15 01:36, Jesper Louis Andersen wrote: 
> > If I remember correctly, you can just go wild and put in all the 
> > parenthesis you want and "go fmt" will clean it up for you wrt 
> > precedence rules 
> > 
> > 
> > On Fri, Apr 14, 2017, 14:38 Elias Naur  > > wrote: 
> > 
> > Your expression is (effectively) ((z*z-x)/2)*z. Use parentheses to 
> > group the 2*z term: (z*z-x)/(2*z). 
> > 
> >   - elias 
> > 
> > 
> > On Friday, April 14, 2017 at 2:30:33 PM UTC+2, ksam...@redhat.com 
> >  wrote: 
> > 
> > Hello, 
> > 
> > Am a newbie to golang, and was trying myself with golang tour. 
> > 
> > 
> > I was trying https://tour.golang.org/flowcontrol/8 and below is 
> > my code snippet for the same 
> > 
> > | 
> > package main 
> > 
> > import ( 
> > "fmt" 
> > "math" 
> > ) 
> > 
> > func Sqrt(x float64) float64 { 
> > z := float64(1) 
> > 
> > for i := 0; i < 10; i++ { 
> > //z = z - (z*z-x)/2*z -- this does not work why ??? 
> > z = z - (float64(z*z)-float64(x))/float64(2*z) 
> > } 
> > return float64(z) 
> > } 
> > 
> > func main() { 
> > fmt.Printf("Ans: %0.2f \n", Sqrt(4)) 
> > fmt.Printf("math.Sqrt: %0.2f", math.Sqrt(4)) 
> > } 
> > 
> > | 
> > 
> > I assume that all data is handled as float64 only, if you see 
> > the commented codes not seem to work especially for simple 
> > Sqrt(4) i get an answer of 1.76 instead of 2 ;) .. but after i 
> > did the casting to float64(..) it seem to work right.. 
> > 
> > I am not able to understand why .. 
> > 
> > any thoughts ? 
> > 
> > -- 
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> > Groups "golang-nuts" group. 
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> > send an email to golang-nuts...@googlegroups.com  
> > . 
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> > 
> > -- 
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>

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Re: [go-nuts] Re: golang tour - floating point numbers

2017-04-16 Thread Janne Snabb 
It does not do this.

It would be nice in most cases if it did.

But some times extra parenthesis are useful for making some formula
easier to read.


Janne Snabb
sn...@epipe.com

On 2017-04-15 01:36, Jesper Louis Andersen wrote:
> If I remember correctly, you can just go wild and put in all the
> parenthesis you want and "go fmt" will clean it up for you wrt
> precedence rules
> 
> 
> On Fri, Apr 14, 2017, 14:38 Elias Naur  > wrote:
> 
> Your expression is (effectively) ((z*z-x)/2)*z. Use parentheses to
> group the 2*z term: (z*z-x)/(2*z).
> 
>   - elias
> 
> 
> On Friday, April 14, 2017 at 2:30:33 PM UTC+2, ksam...@redhat.com
>  wrote:
> 
> Hello,
> 
> Am a newbie to golang, and was trying myself with golang tour. 
> 
> 
> I was trying https://tour.golang.org/flowcontrol/8 and below is
> my code snippet for the same 
> 
> |
> package main
> 
> import (
> "fmt"
> "math"
> )
> 
> func Sqrt(x float64) float64 {
> z := float64(1)
> 
> for i := 0; i < 10; i++ {
> //z = z - (z*z-x)/2*z -- this does not work why ???
> z = z - (float64(z*z)-float64(x))/float64(2*z)
> }
> return float64(z)
> }
> 
> func main() {
> fmt.Printf("Ans: %0.2f \n", Sqrt(4))
> fmt.Printf("math.Sqrt: %0.2f", math.Sqrt(4))
> }
> 
> |
> 
> I assume that all data is handled as float64 only, if you see
> the commented codes not seem to work especially for simple
> Sqrt(4) i get an answer of 1.76 instead of 2 ;) .. but after i
> did the casting to float64(..) it seem to work right.. 
> 
> I am not able to understand why .. 
> 
> any thoughts ?
> 
> -- 
> You received this message because you are subscribed to the Google
> Groups "golang-nuts" group.
> To unsubscribe from this group and stop receiving emails from it,
> send an email to golang-nuts+unsubscr...@googlegroups.com
> .
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> 
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Re: [go-nuts] Re: golang tour - floating point numbers

2017-04-14 Thread Jesper Louis Andersen 
If I remember correctly, you can just go wild and put in all the
parenthesis you want and "go fmt" will clean it up for you wrt precedence
rules

On Fri, Apr 14, 2017, 14:38 Elias Naur  wrote:

> Your expression is (effectively) ((z*z-x)/2)*z. Use parentheses to group
> the 2*z term: (z*z-x)/(2*z).
>
>   - elias
>
>
> On Friday, April 14, 2017 at 2:30:33 PM UTC+2, ksam...@redhat.com wrote:
>>
>> Hello,
>>
>> Am a newbie to golang, and was trying myself with golang tour.
>>
>>
>> I was trying https://tour.golang.org/flowcontrol/8 and below is my code
>> snippet for the same
>>
>> package main
>>
>> import (
>> "fmt"
>> "math"
>> )
>>
>> func Sqrt(x float64) float64 {
>> z := float64(1)
>>
>> for i := 0; i < 10; i++ {
>> //z = z - (z*z-x)/2*z -- this does not work why ???
>> z = z - (float64(z*z)-float64(x))/float64(2*z)
>> }
>> return float64(z)
>> }
>>
>> func main() {
>> fmt.Printf("Ans: %0.2f \n", Sqrt(4))
>> fmt.Printf("math.Sqrt: %0.2f", math.Sqrt(4))
>> }
>>
>>
>> I assume that all data is handled as float64 only, if you see the
>> commented codes not seem to work especially for simple Sqrt(4) i get an
>> answer of 1.76 instead of 2 ;) .. but after i did the casting to
>> float64(..) it seem to work right..
>>
>> I am not able to understand why ..
>>
>> any thoughts ?
>>
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> To unsubscribe from this group and stop receiving emails from it, send an
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[go-nuts] Re: golang tour - floating point numbers

2017-04-14 Thread Elias Naur 
Your expression is (effectively) ((z*z-x)/2)*z. Use parentheses to group 
the 2*z term: (z*z-x)/(2*z).

  - elias

On Friday, April 14, 2017 at 2:30:33 PM UTC+2, ksam...@redhat.com wrote:
>
> Hello,
>
> Am a newbie to golang, and was trying myself with golang tour. 
>
>
> I was trying https://tour.golang.org/flowcontrol/8 and below is my code 
> snippet for the same 
>
> package main
>
> import (
> "fmt"
> "math"
> )
>
> func Sqrt(x float64) float64 {
> z := float64(1)
>
> for i := 0; i < 10; i++ {
> //z = z - (z*z-x)/2*z -- this does not work why ???
> z = z - (float64(z*z)-float64(x))/float64(2*z)
> }
> return float64(z)
> }
>
> func main() {
> fmt.Printf("Ans: %0.2f \n", Sqrt(4))
> fmt.Printf("math.Sqrt: %0.2f", math.Sqrt(4))
> }
>
>
> I assume that all data is handled as float64 only, if you see the 
> commented codes not seem to work especially for simple Sqrt(4) i get an 
> answer of 1.76 instead of 2 ;) .. but after i did the casting to 
> float64(..) it seem to work right.. 
>
> I am not able to understand why .. 
>
> any thoughts ?
>

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