[GRASS-user] Converting raster to polygon creates too many polygons

2010-09-29 Thread Hanlie Pretorius
Hi,

I've created subcatchments using r.watershed and I would like to
convert these to polygons. My result at the moment contains too many
polygons - 194. The original raster had only 9 areas, which should all
have been contiguous seeing that they came from r.watershed.

Here is the sequence of commands that I use, starting with r.report
for the information about the subcatchments raster:
-
 |   Type of Map:  raster   Number of Categories: 18
 |   Data Type:CELL
 |   Rows: 33443
 |   Columns:  33008
 |   Total Cells:  1103886544
 |Projection: Transverse Mercator
 |N: -319.69982072S: -3155672.30728643   Res: 0.8826
 |E: -33474.90929218W: -66483.27873573   Res: 1.1119
 |   Range of data:min = 2  max = 18
-

# Set the resolution to 25m
g.region rast=c83a_border res=25

# Convert the subcatchment raster to vector
r.to.vect --overwrite
input=c83a_dem_25m_clipped_basins_10_clip...@permanent
output=c83a_subcatchme...@permanent feature=area

v.report for the resulting vector gives me 194 categories. The
original raster had only 9 areas, which should all have been
contiguous seeing that they come from r.watershed.

What am I doing wrong? I want an output vector with 9 polygons
corresponding to the original 9 areas in the subcatchment raster.

Thanks
Hanlie
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Re: [GRASS-user] Converting raster to polygon creates too many polygons

2010-09-29 Thread razmjooeis
You might consider using -s flag to smooth the corners.
Otherwise, I can't see why it doesn't work.

R.
Sab

 Hi,

 I've created subcatchments using r.watershed and I would like to
 convert these to polygons. My result at the moment contains too many
 polygons - 194. The original raster had only 9 areas, which should all
 have been contiguous seeing that they came from r.watershed.

 Here is the sequence of commands that I use, starting with r.report
 for the information about the subcatchments raster:
 -
  |   Type of Map:  raster   Number of Categories: 18
  |   Data Type:CELL
  |   Rows: 33443
  |   Columns:  33008
  |   Total Cells:  1103886544
  |Projection: Transverse Mercator
  |N: -319.69982072S: -3155672.30728643   Res:
 0.8826
  |E: -33474.90929218W: -66483.27873573   Res: 1.1119
  |   Range of data:min = 2  max = 18
 -

 # Set the resolution to 25m
 g.region rast=c83a_border res=25

 # Convert the subcatchment raster to vector
 r.to.vect --overwrite
 input=c83a_dem_25m_clipped_basins_10_clip...@permanent
 output=c83a_subcatchme...@permanent feature=area

 v.report for the resulting vector gives me 194 categories. The
 original raster had only 9 areas, which should all have been
 contiguous seeing that they come from r.watershed.

 What am I doing wrong? I want an output vector with 9 polygons
 corresponding to the original 9 areas in the subcatchment raster.

 Thanks
 Hanlie
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Re: [GRASS-user] Converting raster to polygon creates too many polygons

2010-09-29 Thread Micha Silver

On 09/29/2010 02:11 PM, Hanlie Pretorius wrote:

Hi,

I've created subcatchments using r.watershed and I would like to
convert these to polygons. My result at the moment contains too many
polygons - 194. The original raster had only 9 areas, which should all
have been contiguous seeing that they came from r.watershed.

Here is the sequence of commands that I use, starting with r.report
for the information about the subcatchments raster:
-
  |   Type of Map:  raster   Number of Categories: 18
  |   Data Type:CELL
  |   Rows: 33443
  |   Columns:  33008
  |   Total Cells:  1103886544
   


1.1 billion cells. Do you really need that ?

  |Projection: Transverse Mercator
  |N: -319.69982072S: -3155672.30728643   Res: 0.8826
  |E: -33474.90929218W: -66483.27873573   Res: 1.1119
  |   Range of data:min = 2  max = 18
   


It's not 9 areas but 16 categories.


-

# Set the resolution to 25m
g.region rast=c83a_border res=25
   


I don't think changing resolution here will make any difference. (Unless 
you rerun r.watershed after)



# Convert the subcatchment raster to vector
r.to.vect --overwrite
input=c83a_dem_25m_clipped_basins_10_clip...@permanent
output=c83a_subcatchme...@permanent feature=area

v.report for the resulting vector gives me 194 categories. The
original raster had only 9 areas, which should all have been
contiguous seeing that they come from r.watershed.

   


You might be getting many small areas around the edges that are not 
connected with any of the subcatchments.
Displaying the resulting vector should show you where the 194 areas are. 
You might consider getting rid of these edge areas with
v.clean c83a_subcatchments tool=rmsa thresh= 
out=c83a_subcatchments_clean
(choose a threshold large enough to catch all the edge areas, but 
smaller than any of the real subcatchments)




What am I doing wrong? I want an output vector with 9 polygons
corresponding to the original 9 areas in the subcatchment raster.

Thanks
Hanlie
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Re: [GRASS-user] Converting raster to polygon creates too many polygons

2010-09-29 Thread Markus Metz
Hanlie Pretoriuswrote:
 Hi,

 I've created subcatchments using r.watershed and I would like to
 convert these to polygons. My result at the moment contains too many
 polygons - 194. The original raster had only 9 areas, which should all
 have been contiguous seeing that they came from r.watershed.

 Here is the sequence of commands that I use, starting with r.report
 for the information about the subcatchments raster:
 -
  |   Type of Map:  raster               Number of Categories: 18
  |   Data Type:    CELL
  |   Rows:         33443
  |   Columns:      33008
  |   Total Cells:  1103886544
  |        Projection: Transverse Mercator
  |            N: -319.69982072    S: -3155672.30728643   Res: 0.8826
  |            E: -33474.90929218    W: -66483.27873573   Res: 1.1119
  |   Range of data:    min = 2  max = 18
 -

In GRASS, you have full control of the computational region,
consequently you must be able to explain (to the client/supervisor)
every aspect of the computational region. Why is the horizontal
resolution not only slightly off from exactly one meter, but also
different for north-south and east-west? If these are the settings of
the input DEM, why was the DEM created with these settings? If these
resolution settings are different from the DEM's settings, there is
again lots of explaining and justification to do. Life is much easier
with, in this case, exactly 1m resolution which might need to be set
when preprocessing and creating the high-res DEM. The resolution
settings are just slightly different from 1m which can cause rounding
errors later on (export, import, file formats storing resolution in
single and not double precision, other GIS software using single and
not double precision for resolution, etc.)


 # Set the resolution to 25m
 g.region rast=c83a_border res=25
Note that this gives you nsres = 24.99447494 and ewres = 25.00634049,
see comment above. Also note that after converting to vector, the
vector will not match the catchment raster because of the changed
resolution. If you are interested in catchments at 25 meter
resolution, resample the DEM to 25 meter, set the computational region
now, don't touch it later, run r.watershed again, convert catchments
to vector.


 # Convert the subcatchment raster to vector
 r.to.vect --overwrite
 input=c83a_dem_25m_clipped_basins_10_clip...@permanent
 output=c83a_subcatchme...@permanent feature=area

If you use r.to.vect -v, the categories will correspond to cell
values, making it easier to evaluate the vector.

 v.report for the resulting vector gives me 194 categories. The
 original raster had only 9 areas, which should all have been
 contiguous seeing that they come from r.watershed.

The following 5x5 matrix, theoretical example for two basins

1 2 2 2 2
2 1 2 2 2
2 2 1 2 2
2 2 2 1 2
2 2 2 2 2

would be converted not to 2 but to 5 vector areas because the cells
with value 1 are rendered as 4 separate square areas, if you use
r.to.vect -v, with the same category i.e. belonging to the same basin.
BTW, the pattern in the above sample matrix occurs more often with SFD
than with MFD, particularly on such high resolution (roundabout 1m).

Further on, I observed r.to.vect to create redundant areas which can
be removed with v.dissolve.


 What am I doing wrong?

Not much apart from messing with the resolution. g.region res=1 -a or
g.region align=c83a_dem_25m_clipped_basins_10_clipped to cleanly
align a clipped region to a raster map ;-)

 I want an output vector with 9 polygons
 corresponding to the original 9 areas in the subcatchment raster.

You will likely get a vector map with more than 9 areas, but you can
get a vector map with exactly 9 different categories.

Markus M
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Re: [GRASS-user] Converting raster to polygon creates too many polygons

2010-09-29 Thread Hanlie Pretorius
2010/9/29, Markus Metz markus.metz.gisw...@googlemail.com:

 In GRASS, you have full control of the computational region,
 consequently you must be able to explain (to the client/supervisor)
 every aspect of the computational region. Why is the horizontal
 resolution not only slightly off from exactly one meter, but also
 different for north-south and east-west? If these are the settings of
 the input DEM, why was the DEM created with these settings? If these
 resolution settings are different from the DEM's settings, there is
 again lots of explaining and justification to do. Life is much easier
 with, in this case, exactly 1m resolution which might need to be set
 when preprocessing and creating the high-res DEM. The resolution
 settings are just slightly different from 1m which can cause rounding
 errors later on (export, import, file formats storing resolution in
 single and not double precision, other GIS software using single and
 not double precision for resolution, etc.)

Thanks for the extensive comments. I don't really know why the
resolution in the x and y directions are not the same. Even when I set
them explicitly, I get a slight difference:
-
g.region -p vect=c83a_bor...@permanent nsres=25 ewres=25
projection: 99 (Transverse Mercator)
zone:   0
datum:  ** unknown (default: WGS84) **
ellipsoid:  wgs84
north:  -319.69982072
south:  -3155672.30728643
west:   -66483.27873573
east:   -33474.90929218
nsres:  24.99447494
ewres:  25.00634049
rows:   1338
cols:   1320
cells:  1766160
-

The original resolution of the DEM was at 25m resolution. I just
assumend that the differences in x and y resolutions are a result of
the projected surface being skew with respect to the cartesian axes. I
say this because vectors that looked square in a latlong GCS display
slightly skewed when projected to the Transverse Mercator PCS that I
use in this location.

My reason for running r.watershed at a much finer resolution was that
I would get a smoother boundary when I then convert to vector.
Obviously not a good idea.


 Markus M

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Re: [GRASS-user] Converting raster to polygon creates too many polygons

2010-09-29 Thread Markus Metz
Hanlie Pretorius wrote:

 I don't really know why the
 resolution in the x and y directions are not the same. Even when I set
 them explicitly, I get a slight difference:

The -a flag is missing, see my previous post.
 -
 g.region -p vect=c83a_bor...@permanent nsres=25 ewres=25
 projection: 99 (Transverse Mercator)
 zone:       0
 datum:      ** unknown (default: WGS84) **
 ellipsoid:  wgs84
 north:      -319.69982072
 south:      -3155672.30728643
 west:       -66483.27873573
 east:       -33474.90929218
 nsres:      24.99447494
 ewres:      25.00634049
 rows:       1338
 cols:       1320
 cells:      1766160
 -

 The original resolution of the DEM was at 25m resolution. I just
 assumend that the differences in x and y resolutions are a result of
 the projected surface being skew with respect to the cartesian axes. I
 say this because vectors that looked square in a latlong GCS display
 slightly skewed when projected to the Transverse Mercator PCS that I
 use in this location.

Ah, ok, set the computational region in the target location with
Transverse Mercator PCS and align with g.region -a to the desired
resolution, then reproject, then run r.watershed and r.to.vect.


 My reason for running r.watershed at a much finer resolution was that
 I would get a smoother boundary when I then convert to vector.
 Obviously not a good idea.

Someone still has to fix v.generalize for smoothing boundaries...

Markus M
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[GRASS-user] First time GRASS user -- how to import an img dataset?

2010-09-29 Thread Mario Julio Barragan Arce
Hello. I need to learn how to use GIS and I have chosen to do it with GRASS.
My plan is to learn GIS/GRASS essentials during the next 12 months and start
applying it for my research the 12 months after that. I have started reading
the documentation available and playing with the sample data set. However, I
would also like to start playing with a dataset for Puerto Rico (PR) and I
am having problems to import it. How would I go about importing a new
dataset?

In particular, there is a landcover raster image in Erdas img format
(prgap_landcover.img) that I would like to import from here:

ftp://ftp.gap.uidaho.edu/products/Puerto_Rico/GISdata/Landcover/1_Land_cover_grid/

(1) What do I do with this img file? Do I first copy and paste it to my GIS
Data Directory? If not, how do I go about telling GRASS where this file is
(if I want to import it)?

(2) I read about the commands to import raster Erdas/IMG files to GRASS
(r.in.gdal -e in=image.img out=image). If I want to use this command,
should my img file be in the GIS Data Directory first as I suggested in (1)?
Where do I type this command? The GRASS Command Line window seems to open
for an existing Location.

(3) When do I create the location for my data? Do I do this before anything
else?

(4) When trying to create a location from the Location Wizard, I chose as
the method Select coordinate system parameters from a list. I did this
because there is another file in the above mentioned ftp folder with several
parameters which seem to me the kind of information that the wizard asks
(see an excerpt below). From there I chose lcc as the projection code.
However, from here onwards I start having problems. For instance, I don't
know whether to choose Datum with associated ellipsoid or Ellipsoid
only. Also, the wizard asks me Central Parallel, First Standard
Parallel, Second Standard Parallel, and I don't know how that relates to
the two Standard_Parallel parameters given below and where do I get the
other Parallel parameter from? I seem to be missing one. For the geodetic
datum I think I have to choose nad83 and I think I will choose No
transformation at the end of the wizard.

Any suggestions will be very welcome. Thank you in advance. Saludos, Julio.

Spatial_Reference_Information:
  Horizontal_Coordinate_System_Definition:
Planar:
  Map_Projection:
Map_Projection_Name: Lambert Conformal Conic
Lambert_Conformal_Conic:
  Standard_Parallel: 18.03
  Standard_Parallel: 18.43
  Longitude_of_Central_Meridian: -66.43
  Latitude_of_Projection_Origin: 17.83
  False_Easting: 20.00
  False_Northing: 20.00
  Planar_Coordinate_Information:
Planar_Coordinate_Encoding_Method: row and column
Coordinate_Representation:
  Abscissa_Resolution: 15
  Ordinate_Resolution: 15
Planar_Distance_Units: meters
Geodetic_Model:
  Horizontal_Datum_Name: North American Datum of 1983
  Ellipsoid_Name: Geodetic Reference System 80
  Semi-major_Axis: 6378137.00
  Denominator_of_Flattening_Ratio: 298.257222
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[GRASS-user] Open Streep Map

2010-09-29 Thread Mohammed Rashad
How to use openstreetmap data in GRASS GIS. In QGIS I have OSM plugin which
allows to download, modify and upload of data. data can be editted offline
and save changes back to OSM server. How to do these operation using GRASS
GIS. sorry for cross posting

-- 
Rashad
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[GRASS-user] Any GRASS users in Puerto Rico?

2010-09-29 Thread Mario Julio Barragan Arce
Hello. I need to learn how to use GIS and I have chosen to do it with GRASS.
My plan is to learn GIS/GRASS essentials during the next 12 months and start
applying it for my research the 12 months after that. I started reading the
available documentation and also started playing with the sample data set
and am now trying (unsuccessfully) to import data for PR into GRASS. I
realize that I would benefit from discussing many GRASS related issues with
other users and it would be great if I could find someone to discuss with
these issues face to face. There is another person that will be learning
GIS/GRASS with me, so we are already a big GRASS user wannabes in this
campus. Anybody knows of other GRASS users in Puerto Rico we could contact?
Thank you in advance. Saludos, Julio. (I apologize if you get this message
twice as I first mistakenly posted it on a list intended for general GIS and
OsGeo discussion).
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Re: [GRASS-user] First time GRASS user -- how to import an img dataset?

2010-09-29 Thread Micha Silver

On 09/29/2010 06:12 PM, Mario Julio Barragan Arce wrote:
Hello. I need to learn how to use GIS and I have chosen to do it with 
GRASS. My plan is to learn GIS/GRASS essentials during the next 12 
months and start applying it for my 


Welcome, and good decision.
research the 12 months after that. I have started reading the 
documentation available and playing with the sample data set. However, 
I would also like to start playing with a dataset for Puerto Rico (PR) 
and I am having problems to import it. How would I go about importing 
a new dataset?


In particular, there is a landcover raster image in Erdas img format 
(prgap_landcover.img) that I would like to import from here:


ftp://ftp.gap.uidaho.edu/products/Puerto_Rico/GISdata/Landcover/1_Land_cover_grid/

(1) What do I do with this img file? Do I first copy and paste it to 
my GIS Data Directory? If not, how do I go about telling GRASS where 
this file is (if I want to import it)?


If the file is somewhere on your computer, then just enter the path to 
it with the 'input=' parameter to r.in.gdal. Something like:

r.in.gdal in=/path/to/prgap_landcover.img out=prgap_landcover

(BTW, I think you can actually even import into GRASS straight from the 
URL...)


(2) I read about the commands to import raster Erdas/IMG files to 
GRASS (r.in.gdal -e in=image.img out=image). If I want to use this 
command, should my img file be in the GIS Data Directory first as I 
suggested in (1)? Where do I type this command? The GRASS Command Line 
window seems to open for an existing Location.


(3) When do I create the location for my data? Do I do this before 
anything else?


YES, before anything else. This step is crucial, and sometimes confuses 
new users. You *must* have a correct LOCATION defined at the start such 
that it matches the CRS of the original data. GRASS always insists that 
all maps in a LOCATION are projected in exactly the same CRS.
From the metadata below it looks like this file is projected in the LCC 
projection matching the EPSG code of 2866. That's NAD83(HARN) Puerto 
Rico and Virgin Islands.
You might try to first use the wizard to create a new location based on 
this EPSG code. That insures all the parameters get entered properly. 
Then, after starting GRASS in this location (also create a MAPSET - the 
GRASS way to keep maps filed in some directory which is logical for your 
work), try the r.in.gdal command.




(4) When trying to create a location from the Location Wizard, I chose 
as the method Select coordinate system parameters from a list. I did 
this because there is another file in the above mentioned ftp folder 
with several parameters which seem to me the kind of information that 
the wizard asks (see an excerpt below). From there I chose lcc as 
the projection code. However, from here onwards I start having 
problems. For instance, I don't know whether to choose Datum with 
associated ellipsoid or Ellipsoid only. Also, the wizard asks me 
Central Parallel, First Standard Parallel, Second Standard 
Parallel, and I don't know how that relates to the two 
Standard_Parallel parameters given below and where do I get the 
other Parallel parameter from? I seem to be missing one. For the 
geodetic datum I think I have to choose nad83 and I think I will 
choose No transformation at the end of the wizard.


Any suggestions will be very welcome. Thank you in advance. Saludos, 
Julio.


Cheers. For future questions, let us know your OS and version of GRASS. 
And posting the output of commands like g.region -p, v.info, r.info will 
often help.


Regards,
Micha

Spatial_Reference_Information:
   Horizontal_Coordinate_System_Definition:
 Planar:
   Map_Projection:
 Map_Projection_Name: Lambert Conformal Conic
 Lambert_Conformal_Conic:
   Standard_Parallel: 18.03
   Standard_Parallel: 18.43
   Longitude_of_Central_Meridian: -66.43
   Latitude_of_Projection_Origin: 17.83
   False_Easting: 20.00
   False_Northing: 20.00
   Planar_Coordinate_Information:
 Planar_Coordinate_Encoding_Method: row and column
 Coordinate_Representation:
   Abscissa_Resolution: 15
   Ordinate_Resolution: 15
 Planar_Distance_Units: meters
 Geodetic_Model:
   Horizontal_Datum_Name: North American Datum of 1983
   Ellipsoid_Name: Geodetic Reference System 80
   Semi-major_Axis: 6378137.00
   Denominator_of_Flattening_Ratio: 298.257222
   



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[GRASS-user] Multiple arguments in a grass.command- Python

2010-09-29 Thread Luis Lisboa
Greetings

I have a script where I need to define a region based on 2 rasters output[0]
and output[1].

I'm using thwe following expression:
grass.run_command(g.region, rast = output[2] output[3], res= t_srx)

But This is not correct. my question is how can I have both rasters without
getting an error?
(I have tried also with
grass.run_command(g.region, rast = output[2],output[3], res= t_srx) and it
didn't workl

Thanks

Luis
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Re: [GRASS-user] Any GRASS users in Puerto Rico?

2010-09-29 Thread Markus Neteler
On Wed, Sep 29, 2010 at 6:20 PM, Mario Julio Barragan Arce
mariojulio.barra...@upr.edu wrote:
 Hello. I need to learn how to use GIS and I have chosen to do it with GRASS.

Welcome here!

 My plan is to learn GIS/GRASS essentials during the next 12 months and start
 applying it for my research the 12 months after that. I started reading the
 available documentation and also started playing with the sample data set
 and am now trying (unsuccessfully) to import data for PR into GRASS.

Feel free to ask in this mailing list.

 I realize that I would benefit from discussing many GRASS related issues with
 other users and it would be great if I could find someone to discuss with
 these issues face to face. There is another person that will be learning
 GIS/GRASS with me, so we are already a big GRASS user wannabes in this
 campus. Anybody knows of other GRASS users in Puerto Rico we could contact?

BTW: We have a user map here (voluntary registration):
http://grass.osgeo.org/community/

with some registered users (sometimes the background is white when the JPL WMS
temporarily fails) - perhaps you see some names there. Hope you get an answer
here but only a tiny fraction of the GRASS users is subscribed to the
mailing list.

Cheers
Markus
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Re: [GRASS-user] Multiple arguments in a grass.command- Python

2010-09-29 Thread Glynn Clements

Luis Lisboa wrote:

 I have a script where I need to define a region based on 2 rasters output[0]
 and output[1].
 
 I'm using thwe following expression:
 grass.run_command(g.region, rast = output[2] output[3], res= t_srx)
 
 But This is not correct. my question is how can I have both rasters without
 getting an error?
 (I have tried also with
 grass.run_command(g.region, rast = output[2],output[3], res= t_srx) and it
 didn't workl

You can pass lists or tuples for options which accept multiple values,
e.g.:

grass.run_command(g.region, rast = (output[2], output[3]), res= t_srx)
or:
grass.run_command(g.region, rast = [output[2], output[3]], res= t_srx)
or:
grass.run_command(g.region, rast = output[2:4], res= t_srx)

[The last one requires that output is a list or tuple and not e.g. 
an array.]

For a tuple, you need the parentheses to prevent the comma from being
treated as an argument separator.

-- 
Glynn Clements gl...@gclements.plus.com
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[GRASS-user] MDOW relief shading in GRASS

2010-09-29 Thread maning sambale
Hi,

I am revisiting a previous script I made in producing
Multidirectional, oblique-weighted, shaded-relief.  ArcGis has this
script:
http://blogs.esri.com/Support/blogs/mappingcenter/archive/2008/10/07/updated-hillshade-toolbox.aspx

The commads in ARC 6.0.1 GRID by Rober Mark (USGS) are as follows:

shade225 = hillshade(hawaii, 225, 30, shade, 5)
shade270 = hillshade(hawaii, 270, 30, shade, 5)
shade315 = hillshade(hawaii, 315, 30, shade, 5)
shade360 = hillshade(hawaii, 360, 30, shade, 5)
h00 = resample(hawaii, 1000)
h01 = focalmean(h00)
h02 = focalmean(h01)
h03 = focalmean(h02)
asp = aspect(h03)
asp1 = con(isnull(asp), 293, asp)
w225 = sqr(sin((asp1 - 225) div deg ))
w270 = sqr(sin((asp1 - 270) div deg))
w315 = sqr(sin((asp1 - 315) div deg ))
w360 = sqr(sin(asp1 div deg ))
setcell minof
temp = w225 * shade225 + w270 * shade270 + w315 *
shade315 + w360 * shade360
shade4 = int(temp div 2)

I tried porting in GRASS shell:

g.region rast=$GIS_OPT_input -p

# Compute hillshade at azimuth 225, 270, 315 and 360 at 30 degrees sun
illumination angle
r.shaded.relief map=$GIS_OPT_input shadedmap=shade225 altitude=30
azimuth=225 zmult=1 scale=1
r.shaded.relief map=$GIS_OPT_input shadedmap=shade270 altitude=30
azimuth=270 zmult=1 scale=1
r.shaded.relief map=$GIS_OPT_input shadedmap=shade315 altitude=30
azimuth=315 zmult=1 scale=1
r.shaded.relief map=$GIS_OPT_input shadedmap=shade360 altitude=30
azimuth=360 zmult=1 scale=1

# Resample DEM map
r.neighbors in=$GIS_OPT_input out=res1 method=average size=$GIS_OPT_window

# compute aspect map
r.slope.aspect elevation=res1 format=degrees prec=float aspect=aspect
zfactor=1.0 min_slp_allowed=0.0

# compute weights 225, 270, 315 and 360
r.mapcalc w225 = sin((aspect - 225)*sin(aspect - 225))
r.mapcalc w270 = sin((aspect - 270)*sin(aspect - 270))
r.mapcalc w315 = sin((aspect - 315)*sin(aspect - 315))
r.mapcalc w360 = sin((aspect)*sin(aspect))


#compute weighted
r.mapcalc weightedshade = (((w225 * shade225) + (w270 * shade270) +
(w315 * shade315) + (w360 * shade360))/2)
r.colors map=weightedshade color=grey

But I get not so good results, here's the output using nc_sp_08's
elev_ned_30m (X0=MDOW, X1= default r.shaded.relief module)
http://farm5.static.flickr.com/4148/5037622535_113924312b_b.jpg

Anything wrong with my commands?

-- 
cheers,
maning
--
Freedom is still the most radical idea of all -N.Branden
wiki: http://esambale.wikispaces.com/
blog: http://epsg4253.wordpress.com/
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