On Wednesday, February 22, 2012, Paolo Cavallini wrote:
Il 22/02/2012 15:54, Roger Bivand ha scritto:
Using the improved raster graphics handling for square cells with image()
rather than spplot() and useRaster=TRUE - equivalent to
image.SpatialGridDataFrame() and useRasterImage=TRUE with
Il 06/03/2012 22:32, Dylan Beaudette ha scritto:
Check out the plot() function from the raster package, or the related
rasterViz (?) package. They have some neat stuff in there.
Roger already mentioned this, but I'll add a little more. Now that we have
Thanks for your comments. Please note
Rely on hexbin() instead of plot()
hb - hexbin(your_independent_var, your_dependent_var, xbins = 40)
plot(hb)
Duccio
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Just 2k may mean 4 million rectangles. R display is vector, hard-copy, with
some recent support for raster grids when the rectangles are in fact square.
As has been said, the graphics engine is not designed for fast screen
output, but for scientific statistical graphics.
spplot uses lattice
Il 22/02/2012 15:54, Roger Bivand ha scritto:
Using the improved raster graphics handling for square cells with image()
rather than spplot() and useRaster=TRUE - equivalent to
image.SpatialGridDataFrame() and useRasterImage=TRUE with the same matrix
takes 1.2 seconds on x11/cairo. You didn't say
roger.biv...@nhh.no
Subject: [GRASS-user] Re: spgrass6
To: grass-user@lists.osgeo.org
Message-ID: 1329922472770-4495201.p...@n6.nabble.com
Content-Type: text/plain; charset=us-ascii
Just 2k may mean 4 million rectangles. R display is vector, hard-copy, with
some recent support for raster grids when
