Dear list,
I am struggling with my python code.
I am trying to get the computational region of a xyz-file. If I use
r.in.xyz in GRASS itself, it works all just fine, but using it in python
I always get an error.
Here is my code:
from grass_session import Session
from grass.script import
thanks for the answers, but this did not work.
Again, here is my code, this time not just the minimum version:
#!/usr/bin/env python
import os
from grass_session import Session
from grass.script import core as gcore
from grass.pygrass.modules.shortcuts import general as g
from grass.pygrass.modu
36 b=159.04 t=206.46
res=1 -p ended with error
Process ended with non-zero return code 1. See errors in the (error)
output.
#
This leads to the question, how the input for g.region should look like
in python?
Again, any help is appreciated :)
best regards
Am 1
t error disappeared, but now I have a new one.
running < g.region n=5611999 s=561 e=32361999 w=3236 b=159.04
t=206.46 res=1 -p > from command line in GRASS works just fine.
Any help appreciated
Jonathan
Am 19.02.2018 um 18:49 schrieb Pietro:
> Thank you Anna I did not noticed
Nope, still the same error
Am 26.02.2018 um 15:35 schrieb Anna Petrášová:
> Would
>
> parse=(grass.parse_key_val, {'sep': '=', 'vsep': ' '}))
>
> help?
>
> On Mon, Feb 26, 2018 at 4:53 AM, Jonathan Reith wrote:
>> Ok. So n
7;676 s=887 e=88 w=4'}
>
> which is what you are getting. But with adding space as vsep, I get
> correct results, so it should work. Are you sure you used space there?
>
> grass.parse_key_val('n=676 s=887 e=88 w=4', sep='=', vsep=' ')
>
>
