On Mon, Feb 26, 2018 at 3:49 PM, Jonathan Reith wrote:
> Ok, now it works. Thanks a lot. My test-file made some problems, but now
> it finally works :)
Great!
I have updated the Wiki code snippet to a working example
https://grasswiki.osgeo.org/wiki/GRASS_Python_Scripting_Library#Example_for_par
Ok, now it works. Thanks a lot. My test-file made some problems, but now
it finally works :)
Am 26.02.2018 um 15:42 schrieb Anna Petrášová:
> When I try this:
>
> grass.parse_key_val('n=676 s=887 e=88 w=4', sep='=')
>
> I get:
>
> {u'n': u'676 s=887 e=88 w=4'}
>
> which is what you are getting. B
When I try this:
grass.parse_key_val('n=676 s=887 e=88 w=4', sep='=')
I get:
{u'n': u'676 s=887 e=88 w=4'}
which is what you are getting. But with adding space as vsep, I get
correct results, so it should work. Are you sure you used space there?
grass.parse_key_val('n=676 s=887 e=88 w=4', sep=
Nope, still the same error
Am 26.02.2018 um 15:35 schrieb Anna Petrášová:
> Would
>
> parse=(grass.parse_key_val, {'sep': '=', 'vsep': ' '}))
>
> help?
>
> On Mon, Feb 26, 2018 at 4:53 AM, Jonathan Reith wrote:
>> Ok. So now my code is:
>>
>> compregion = grass.parse_command("r.in.xyz", inpu
Would
parse=(grass.parse_key_val, {'sep': '=', 'vsep': ' '}))
help?
On Mon, Feb 26, 2018 at 4:53 AM, Jonathan Reith wrote:
> Ok. So now my code is:
>
> compregion = grass.parse_command("r.in.xyz", input=xyz,
> separator="space", flags="sg", output="bbox",parse=(grass.parse_key_val,
> {'sep'
Ok. So now my code is:
compregion = grass.parse_command("r.in.xyz", input=xyz,
separator="space", flags="sg", output="bbox",parse=(grass.parse_key_val,
{'sep': '='}))
print(compregion)
g.region(res="1", flags="p", **compregion)
and the output:
{u'n': u'5611999 s=561 e=32361999 w=
On Mon, Feb 19, 2018 at 6:49 PM, Pietro wrote:
> On 19 Feb 2018 4:41 p.m., "Jonathan Reith" wrote:
>
> print(compregion)
> g.region(compregion,res="1", flags="p")
>
> you are hassling the dictionary to a region, but you have to unpack the
> dictionary just write:
>
> ...
>
> g.region(res="1",
Thank you Anna I did not noticed the underscor...
On 19 Feb 2018 4:41 p.m., "Jonathan Reith" wrote:
print(compregion)
g.region(compregion,res="1", flags="p")
you are hassling the dictionary to a region, but you have to unpack the
dictionary just write:
...
g.region(res="1", flags="p", **c
Ok, now I understood the problem, thanks a lot Anna
But I'm still struggling with the parse_command and r.in.xyz
code-example:
compregion = grass.parse_command("r.in.xyz",input="tmp.xyz",
separator="space", flags="sg", output="bbox",
parse=(grass.parse_key_val,
On Mon, Feb 19, 2018 at 4:36 AM, Jonathan Reith wrote:
> thanks for the answers, but this did not work.
>
> Again, here is my code, this time not just the minimum version:
>
> #!/usr/bin/env python
> import os
> from grass_session import Session
> from grass.script import core as gcore
>
> from gr
thanks for the answers, but this did not work.
Again, here is my code, this time not just the minimum version:
#!/usr/bin/env python
import os
from grass_session import Session
from grass.script import core as gcore
from grass.pygrass.modules.shortcuts import general as g
from grass.pygrass.modu
Isn't the problem that you have there r.in_xyz instead of r.in.xyz?
Anna
On Feb 12, 2018 9:35 AM, "Pietro" wrote:
Dear Jonathan,
the error is due to grass_session that is not creating the location if
missing.
I don't have time in this day to fix this issue in grass_session, so the
fastest fsol
Dear Jonathan,
the error is due to grass_session that is not creating the location if
missing.
I don't have time in this day to fix this issue in grass_session, so the
fastest fsolution at the momenth is to check and create what is needed step
by step.
I did not have xyz file to test so I've only
13 matches
Mail list logo
