On 21/06/16 13:56, Tsjerk Wassenaar wrote:
Hi David,
And why the number of frames?
Whoopsydaises. You're absolutely right.
Cheers,
Tsjerk
On Tue, Jun 21, 2016 at 9:52 AM, David van der Spoel
wrote:
On 21/06/16 09:40, Qasim Pars wrote:
Dear David,
Could you
Hi David,
And why the number of frames?
Cheers,
Tsjerk
On Tue, Jun 21, 2016 at 9:52 AM, David van der Spoel
wrote:
> On 21/06/16 09:40, Qasim Pars wrote:
>
>> Dear David,
>>
>> Could you please more explain each term of the formula you said?
>>
>> Formula=The number of
On 21/06/16 10:25, Billy Williams-Noonan wrote:
A related problem, when I compute the entropy for:
= - -
I get a T of -8640 kJ/mol (or =-28.9 kJ/mol/K)
Unit for S is J/mol K.
This value seems inordinately high...
If T was actually -28.9 kJ/mol that
A related problem, when I compute the entropy for:
= - -
I get a T of -8640 kJ/mol (or =-28.9 kJ/mol/K)
This value seems inordinately high...
If T was actually -28.9 kJ/mol that would match well with experimental
data given my enthalpy.
I am selecting
On 21/06/16 09:40, Qasim Pars wrote:
Dear David,
Could you please more explain each term of the formula you said?
Formula=The number of atoms (N * 3)^2 times number of frames times 4 bytes
Why square the number of atoms?
Because we build a matrix of all degrees of freedom.
Why 4 bytes?
The
Dear David,
Could you please more explain each term of the formula you said?
Formula=The number of atoms (N * 3)^2 times number of frames times 4 bytes
Why square the number of atoms?
Why 4 bytes?
Thanks in advance
> On 21 Jun 2016, at 09:39, David van der Spoel wrote:
Thank you David! :)
On 21 June 2016 at 17:24, David van der Spoel wrote:
> On 21/06/16 08:54, Billy Williams-Noonan wrote:
>
>> Thanks for your reply, I think this is helping.
>>
>>Using your equation above I would need about 82TB for 1000 frames...
>> I
>> somehow
On 21/06/16 08:54, Billy Williams-Noonan wrote:
Thanks for your reply, I think this is helping.
Using your equation above I would need about 82TB for 1000 frames... I
somehow feel that this would be inaccessible for any calculation using just
one node, which is a requirement for g_covar.
Apologies... For the 50 frames (not 1000) I have been using, it would take
4.1 TB of RAM. This still seems a bit high.
On 21 June 2016 at 16:54, Billy Williams-Noonan <
billy.williams-noo...@monash.edu> wrote:
> Thanks for your reply, I think this is helping.
>
>Using your equation above I
Thanks for your reply, I think this is helping.
Using your equation above I would need about 82TB for 1000 frames... I
somehow feel that this would be inaccessible for any calculation using just
one node, which is a requirement for g_covar.
I could reduce the frames but I think I would wind
On 21/06/16 08:11, Billy Williams-Noonan wrote:
Sorry, the original post provides an example of the -dt flag with 100ps
intervals.
You can calculate how much space you need by number of atoms (N * 3)^2
times number of frames times 4 bytes.
Do you select just your biomolecule?
On 21 June
Sorry, the original post provides an example of the -dt flag with 100ps
intervals.
On 21 June 2016 at 16:10, Billy Williams-Noonan <
billy.williams-noo...@monash.edu> wrote:
> Thank you for your reply. :)
>
>My main problem is with gmx covar which does not have a -skip flag. As
> you can
Thank you for your reply. :)
My main problem is with gmx covar which does not have a -skip flag. As
you can see from the OP I have tried the -dt flag with 250ps intervals. It
still crashes due to insufficient memory. It also crasses with 5000ps
intervals, giving me just 20ps of frames to
On 21/06/16 07:34, Billy Williams-Noonan wrote:
Hi Gromacs Users,
I am running g_mmpbsa.py to calculate the binding enthalpy of a cyclic
peptide in a drug target. At the same time I am trying to generate
ensemble estimates for entropy for the protein, ligand and complex. By
using these two
Hi Gromacs Users,
I am running g_mmpbsa.py to calculate the binding enthalpy of a cyclic
peptide in a drug target. At the same time I am trying to generate
ensemble estimates for entropy for the protein, ligand and complex. By
using these two variables I aim to get an idea of the Gibbs free
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