0.67 moles/L * 2440.78 nm^3 = 0.67 moles* 2.4408*x10^-21
0.67*6.022141x10^23 molecules * 2.4408*x10^-21 = 0.67 * 1470 molecules
0.67 * 1470 = 984.9 molecules
You would need ~985 molecules in your box to fulfill your molar concentration.
From: gromacs.org_gmx-users-boun...@maillist.sys.kth.se
on behalf of Pandya, Akash
Sent: Thursday, May 18, 2017 8:52 AM
To: gromacs.org_gmx-users@maillist.sys.kth.se
Subject: [gmx-users] Calculating number of molecules to add in simulation box
Hi all,
I'm trying to calculate the number of Glycine molecules to add into the
simulation box. The molar concentration of glycine I'm using is 0.67M. My
simulation box size is 2nm and the box volume is 2440.78nm^3. How would I
calculate the number of glycine molecules to fulfil this molar concentration?
Best wishes,
Akash
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