RE: [Harbour] exit with switch and for each

2009-05-27 Thread Horodyski Marek (PZUZ)
-Original Message- From: Przemyslaw Czerpak [mailto:dru...@acn.waw.pl] Sent: Monday, May 25, 2009 9:40 PM To: Harbour Project Main Developer List. Subject: Re: [Harbour] exit with switch and for each On Sat, 23 May 2009, Vailton Renato wrote: [...] The same is for many other

Re: RE: [Harbour] exit with switch and for each

2009-05-27 Thread Przemyslaw Czerpak
On Wed, 27 May 2009, Horodyski Marek (PZUZ) wrote: This is not comparable. Exit was escape from loop without control expression, loop with control. Now, when mixed syntax switch and any while/for we still heve LOOP inside switch, but EXIT no longer. EXIT in the sense : escape from a loop.

RE: [Harbour] exit with switch and for each

2009-05-25 Thread Horodyski Marek (PZUZ)
Yes, therefore I write without additive rules. Regards, Marek Horodyski -Original Message- From: Vailton Renato [mailto:vail...@gmail.com] Sent: Saturday, May 23, 2009 10:06 PM To: Harbour Project Main Developer List. Subject: Re: [Harbour] exit with switch and for each Here I use

Re: [Harbour] exit with switch and for each

2009-05-25 Thread Ranier Vilela
Horodyski Marek (PZUZ) escreveu: Yes, therefore I write without additive rules. Regards, Marek Horodyski -Original Message- From: Vailton Renato [mailto:vail...@gmail.com] Sent: Saturday, May 23, 2009 10:06 PM To: Harbour Project Main Developer List. Subject: Re: [Harbour] exit

Re: [Harbour] exit with switch and for each

2009-05-25 Thread Przemyslaw Czerpak
On Sat, 23 May 2009, Vailton Renato wrote: Hi, Here I use something like this: lExit := .F. for each x in stringORarray switch x case 'a' lExit := .T. exit // but we need exit from for each, not only from switch end if lExit exit; end next The same is for many other