RE: Haskell 2 -- Dependent types?

1999-02-17 Thread michael abbott
As a C++ user (with a background in categories) patiently waiting for something a lot better, I personally favour two principles: 1. let's go for undecidable type checking. I want the compiler to be able to do as much work as possible: ideally, everything that can be resolved at compile

Query re gcd() in Haskell 98

1999-02-01 Thread michael abbott
special testing. Regarding the integers =0 as a partial order with a=b when a|b (a divides b) then gcd a b is the lattice meet of a and b, and 0 is the top element. Defining gcd 0 x = 0 is consistent with this, for any x. Michael Abbott