I need a class tree for haskell. where can i find it?
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Hi Ashley,
Hugs currently restricts the way constrained existential types
may be formed, for entirely internal, technical reasons. We're
currently looking over the implementation to see if it's
possible to lift the restriction without rewriting substantial
parts of the type checker.
-- Joha
Andreas Leitner wrote at the end of his discussion about
constants/functions sans arguments:
> I mean couldn't one say that there are no constants, just functions
> with no arguments or the Void/Unit argument that return an expression.
> Since we have lazy evaluation, there won't be a problem at
Ive just decided to start with haskell (after a decade of OO, and a few month
of erlang (already impressive))
despite i love linux, id like to stay with wintel, to be able to use it at the
office, and try to slot it in my daily job, slowly.
(doing some modeling, should be useful)
1)are ther
Andreas Leitner wrote:
> Hi,
>
> I hope this is the right forum to post my question to.
>
> Given a lazy pure functional language do we need to differntiate (in
> syntax) between constants and functions without agruments? And if we
> don't need to, does Haskell make a difference?
>From a pedanti
> I am using the library oncurrent of GHC. I'd like to know how two
> different threads can communicate each other.
> To solve the problem I thought in something like a global variable. If
> there any method to avoid the use of that kind of variables
> in haskell.
You can use the various concur
Hello,
I am using the library oncurrent of GHC. I'd like to know how two
different threads can communicate each other.
To solve the problem I thought in something like a global variable. If
there any method to avoid the use of that kind of variables in haskell.
Thanks in advance
J. I. García
Tom Pledger wrote:
>
> Andreas Leitner writes:
> :
> | Given a lazy pure functional language do we need to differntiate
> | (in syntax) between constants and functions without agruments? And
> | if we don't need to, does Haskell make a difference?
>
> Haskell always treats a declaration of t
