Djinn takes a type, what you have written does not appear to be a type.
-- Lennart
On Thu, Apr 7, 2011 at 3:35 PM, Martin wrote:
>
> After reading this post, i can only see a -> b
>
> how to define more specific such as
>
> flow 0 y = y
> flow z flow x, y = flow z+x, y
>
> could you demonstra
On 7 April 2011 14:35, Martin wrote:
>
> flow 0 y = y
> flow z flow x, y = flow z+x, y
This doesn't appear to be a valid function definition...
--
Ivan Lazar Miljenovic
ivan.miljeno...@gmail.com
IvanMiljenovic.wordpress.com
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After reading this post, i can only see a -> b
how to define more specific such as
flow 0 y = y
flow z flow x, y = flow z+x, y
could you demonstrate using djinn to do above mapping definition
to generate a function?
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lennart:
> Howdy, y'all!
>
> I've written a small program that takes a (Haskell) type
> and gives you back a function of that type if one exists.
> It's kind of fun, so I thought I'd share it.
>
> It's probably best explained with a sample session.
>
> calvin% djinn
> Welcome to Djinn versio
Howdy, y'all!
I've written a small program that takes a (Haskell) type
and gives you back a function of that type if one exists.
It's kind of fun, so I thought I'd share it.
It's probably best explained with a sample session.
calvin% djinn
Welcome to Djinn version 2005-12-11.
Type :h to g