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On 8/4/10 17:16 , Andrew Coppin wrote:
I have a vague recollection of there being a situation to do with calling
foreign code that makes all Haskell threads block in the non-threaded RTS,
but not in the threaded one. Depending on how big your send
On Thu, Aug 5, 2010 at 1:29 PM, Ivan Lazar Miljenovic
ivan.miljeno...@gmail.com wrote:
On 5 August 2010 13:23, Mark Wotton mwot...@gmail.com wrote:
Might it be possible to enable multiple maintainers on packages, each
of whom can upload new versions? As far as I can tell, that's not
currently
On 5 August 2010 13:32, Mark Wotton mwot...@gmail.com wrote:
On Thu, Aug 5, 2010 at 1:29 PM, Ivan Lazar Miljenovic
ivan.miljeno...@gmail.com wrote:
On 5 August 2010 13:23, Mark Wotton mwot...@gmail.com wrote:
Might it be possible to enable multiple maintainers on packages, each
of whom can
Ivan Lazar Miljenovic wrote:
On 5 August 2010 13:32, Mark Wotton mwot...@gmail.com wrote:
On Thu, Aug 5, 2010 at 1:29 PM, Ivan Lazar Miljenovic
ivan.miljeno...@gmail.com wrote:
On 5 August 2010 13:23, Mark Wotton mwot...@gmail.com wrote:
Might it be possible to enable multiple
The documentation is a little confusing on this issue. It sounded to
me when I read the documentation that all of the *OS* threads were
blocked by the FFI, when what was meant was that all of the *IO* threads
assigned to the calling OS thread are what is blocked, because the docs
just say
On Tue, Aug 3, 2010 at 9:45 PM, Ryan Ingram ryani.s...@gmail.com wrote:
So I believe the final way to do this, which is not yet implemented,
works something like this:
type family LeftToRight a
type family RightToLeft b
class (LeftToRight a ~ b, RightToLeft b ~ a) = Bijection a b where
On 4 August 2010 03:45, Ryan Ingram ryani.s...@gmail.com wrote:
So I believe the final way to do this, which is not yet implemented,
works something like this:
type family LeftToRight a
type family RightToLeft b
class (LeftToRight a ~ b, RightToLeft b ~ a) = Bijection a b where
...
I
Hi All:
I have been trying to use System.timeout in windows, but for some
reason it doesn't work, a concrete example is:
import Network.HTTP
import System.Timeout
main = do
rsp - timeout 1000 $ simpleHTTP $ getRequest http://10.1.2.3;
case rsp of
Just rsp - print $ show rsp
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