[Haskell-cafe] How to convert records into Haskell structure in Haskell way?

Hi, Say I have something like this: [ Record { item = A1, value = 0 } , Record { item = B1, value = 13 } , Record { item = A2, value = 2 } , Record { item = B2, value = 10 } ] How to convert it into: [ XXInfo { name = A, value1 = 0, value2 = 2 } , XXInfo { name = B, value1 = 13, value2 = 10 }

Re: [Haskell-cafe] How to convert records into Haskell structure in Haskell way?

Am Dienstag 03 November 2009 02:29:56 schrieb Magicloud Magiclouds: Hi, Say I have something like this: [ Record { item = A1, value = 0 } , Record { item = B1, value = 13 } , Record { item = A2, value = 2 } , Record { item = B2, value = 10 } ] How to convert it into: [ XXInfo { name =

Re: [Haskell-cafe] How to convert records into Haskell structure in Haskell way?

On Mon, Nov 2, 2009 at 5:29 PM, Magicloud Magiclouds magicloud.magiclo...@gmail.com wrote: Hi,  Say I have something like this: [ Record { item = A1, value = 0 } , Record { item = B1, value = 13 } , Record { item = A2, value = 2 } , Record { item = B2, value = 10 } ]  How to convert it