--- Chris Kuklewicz [EMAIL PROTECTED]
wrote:
I have two strong suggestions:
* whoever does submit them should diff the output
with a previously accepted version.
-snip-
Simply diff program output with the example output
file (there's now an output file link in each problem
description).
Of
On 09.01 12:56, Donald Bruce Stewart wrote:
Entries that may currently be worth submitting:
takfp - http://www.haskell.org/hawiki/TakfpEntry
Committed.
pidigits (currently 2nd!) - http://www.haskell.org/hawiki/PidigitsEntry
Committed.
mandelbrot
ekarttun:
On 09.01 12:56, Donald Bruce Stewart wrote:
Entries that may currently be worth submitting:
takfp - http://www.haskell.org/hawiki/TakfpEntry
Committed.
pidigits (currently 2nd!) - http://www.haskell.org/hawiki/PidigitsEntry
Committed.
Donald Bruce Stewart wrote:
Entries that may currently be worth submitting:
takfp - http://www.haskell.org/hawiki/TakfpEntry
pidigits (currently 2nd!) - http://www.haskell.org/hawiki/PidigitsEntry
mandelbrot-
Donald Bruce Stewart wrote:
d:
Regarding the Fannkuch Shootout Entry:
If we are willing to specialize flop in the way shown on the wiki,
another 8% can be gained by similarly specializing rotate:
rotate 2 (x1:x2:xs) = x2:x1:xs
rotate 3 (x1:x2:x3:xs) = x2:x3:x1:xs
...
Cheers,
bertram.felgenhauer:
The flop machinery can still be made faster, stealing an idea from the
icc entry (namely, treating the first entry separately):
Great. This pushes the pure version up a notch.
I've updated the wiki, showing how the code has progressed:
Author Time in
Hi All,
Regarding the Fannkuch Shootout Entry:
If we are willing to specialize flop in the way shown on the wiki,
another 8% can be gained by similarly specializing rotate:
rotate 2 (x1:x2:xs) = x2:x1:xs
rotate 3 (x1:x2:x3:xs) = x2:x3:x1:xs
rotate 4 (x1:x2:x3:x4:xs) = x2:x3:x4:x1:xs
rotate
d:
Regarding the Fannkuch Shootout Entry:
If we are willing to specialize flop in the way shown on the wiki,
another 8% can be gained by similarly specializing rotate:
rotate 2 (x1:x2:xs) = x2:x1:xs
rotate 3 (x1:x2:x3:xs) = x2:x3:x1:xs
...
Cheers, I've updated the proposed entry on the
