Here is my trivial program:
import Bits
main = putStr (show(bit 0::Int)++ ++show (mybit 0))
mybit:: Int - Int
mybit x = setBit (bit 0) x
The output (with GHC-5) is
1 1
My question: Why is (bit 0) equal to 1 and not 0? That first bit is set
regardless of the value of x (I have tried
On 11/13/05, Murray Gross [EMAIL PROTECTED] wrote:
Here is my trivial program:
import Bits
main = putStr (show(bit 0::Int)++ ++show (mybit 0))
mybit:: Int - Int
mybit x = setBit (bit 0) x
The output (with GHC-5) is
1 1
My question: Why is (bit 0) equal to 1 and not 0?
If only
On Sun, 13 Nov 2005, Lemmih wrote:
'setBit (bit 0) 4' = 'setBit 1 4' = (binary) 10001 = (dec) 17
OK, what you are saying is that I have misinterpreted the behavior of bit,
which I thought only did a conversion, but in fact sets the zero-th
bit of a bit string. I have checked that this is in
