Definitely I'll take this solution, I'm reading about Pointfree, I think it's
not that dificult to understand. And moreover it's the simpliest way to
write code.
Jón Fairbairn-2 wrote:
>
> Andrea Rossato <[EMAIL PROTECTED]> writes:
>
>> On Mon, Sep 18, 2006 at 04:16:55AM -0700, Carajillu wrote
On Mon, Sep 18, 2006 at 05:35:47AM -0700, Carajillu wrote:
> I'm testing it and it's working really well. The other solutions are a
> little complicated for me, but I'm still trying to undestand them.
Jón's approach (the last version of his message), usually cleaner and
more concise, is called poi
On Mon, Sep 18, 2006 at 02:52:45PM +0200, Andrea Rossato wrote:
> On Mon, Sep 18, 2006 at 05:42:47AM -0700, Carajillu wrote:
> >
> > Not a good solution, it just substitutes the first occurrence of the item in
> > the list. I'll try the others
>
> I did not get this point.
> You must take Jón's a
On Mon, Sep 18, 2006 at 05:42:47AM -0700, Carajillu wrote:
>
> Not a good solution, it just substitutes the first occurrence of the item in
> the list. I'll try the others
I did not get this point.
You must take Jón's approach with map.
andrea
___
Haske
Hello Andrea,
Monday, September 18, 2006, 3:22:43 PM, you wrote:
> substitute e l1 l2= [c | c <- check_elem l1]
why not just
substitute e l1 l2= check_elem l1
? :)
> where check_elem [] = l1
should be
where check_elem [] = []
otherwise you just append second (backup? :) copy of or
Not a good solution, it just substitutes the first occurrence of the item in
the list. I'll try the others
Carajillu wrote:
>
> Finally I took Andrea's solution "check_elem (x:xs) = if x == e then (l2
> ++ xs) else [x] ++ check_elem xs"
> I think it's easy to understand for me ( in my noob level
Finally I took Andrea's solution "check_elem (x:xs) = if x == e then (l2 ++
xs) else [x] ++ check_elem xs"
I think it's easy to understand for me ( in my noob level), than the
recursive one.
I'm testing it and it's working really well. The other solutions are a
little complicated for me, but I'm
Hello Carajillu,
Monday, September 18, 2006, 1:51:34 PM, you wrote:
> Hi, I'm a student and I have to do a program with Haskell. This is the first
> time I use this languaje, and I'm having problems with the indentation. I
> want to check if this function is correct, but when I try to make the GH
On Mon, Sep 18, 2006 at 12:25:21PM +0100, Neil Mitchell wrote:
> Why not:
> > check_elem (x:xs) = if x == e then (l2 ++ xs) else x : check_elem xs
>
> Thanks
Thank you!
Lists are my personal nightmare...;-)
Andrea
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Hi
check_elem (x:xs) = if x == e then (l2 ++ xs) else [x] ++ check_elem
xs
Why not:
check_elem (x:xs) = if x == e then (l2 ++ xs) else x : check_elem xs
Thanks
Neil
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On Mon, Sep 18, 2006 at 04:16:55AM -0700, Carajillu wrote:
>
> Wow! I'm starting to love this languaje, and the people who uses it!:)
>
You spoke too early. My code had a bug, a huge one...
this is the right one:
-- Replaces a wildcard in a list with the list given as the third argument
substi
Wow! I'm starting to love this languaje, and the people who uses it!:)
Andrea Rossato wrote:
>
> On Mon, Sep 18, 2006 at 12:54:34PM +0200, Albert Crespi wrote:
>> Thank you very much for your reply!
>> As I said, it is my first experience with Haskell, I have been
>> programming
>> in Java and
On Mon, Sep 18, 2006 at 12:54:34PM +0200, Albert Crespi wrote:
> Thank you very much for your reply!
> As I said, it is my first experience with Haskell, I have been programming
> in Java and C for some years, and I find this language very different from
> them. Anyway I'll try to fix the function
Carajillu <[EMAIL PROTECTED]> writes:
> I get "line 18:parse error (possibly incorrect indentation)"
..which is a bit misleading, as the problem is on the preceeding line
of code.
> if x == e then return l2
And if x /= e? What is check_elem then?¹
> -- Tries to match two lists
On Mon, Sep 18, 2006 at 02:51:34AM -0700, Carajillu wrote:
>
> Hi, I'm a student and I have to do a program with Haskell. This is the first
> time I use this languaje, and I'm having problems with the indentation. I
> want to check if this function is correct, but when I try to make the GHCi
> int
Hi, I'm a student and I have to do a program with Haskell. This is the first
time I use this languaje, and I'm having problems with the indentation. I
want to check if this function is correct, but when I try to make the GHCi
interpret it, I get "line 18:parse error (possibly incorrect indentation
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