Thank you Benedikt!
Thanks to your help I also figured out the way to do it using type families
yesterday:
class Pro p where
type I p
type O p
re :: p → [I p → O p]
instance Pro (b → c) where
type I (b → c) = b
type O (b → c) = c
re = repeat
instance Pro [b → c] where
Cetin Sert schrieb:
Hi,
class Processor a where
ready :: (forall b c. a → [b → c])
instance Processor (b → c) where
ready = repeat
...
---
Why can I not declare the above instances and always get:
Hi Cetin,
in your class declaration you state that a
module Main where
import Control.Monad
import Control.Concurrent
class Processor p where
ready :: p b c → [b → c]
instance Processor (→) where
ready = repeat
--instance Processor [b → c] where
--ready = id
newtype FunList b c = FunList [b → c]
instance Processor FunList where
ready
Cetin Sert schrieb:
Thank you for your answer!
This comes close to solving the problem but in the last line of the
above I want to be able to say:
either
print $ broadcast id [1..10]
or
print $ broadcast [ (x +) | x ← [1..10] ] [1..10]
both need to be possible*.
So is there
