Neil Rutland wrote:
stops :: int->int->int
I think that says that the function stops takes two integers and returns
an integer.
This is correct (though as someone else pointed out, Haskell types start
with a capital letter).
What i'm not entirely sure of is how i'd then write the function itself
because i literally want it to have the following form
stops (x,y) = x+y
As "stops" just adds numbers, it is equivalent to the + operator, so you
don't have to write a function at all. It doesn't do any harm to write
a function, but the simplest way of expressing "stops" is this:
stops :: Int -> Int -> Int
stops = (+)
One of the benefits of a functional language is that you can assign
functions as well as data!
Pete
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