On 7/25/06, Jared Updike [EMAIL PROTECTED] wrote:
I am trying to derive MyOrd class from Eq (Prelude):
class Eq a = MyOrd a where
(%=), (%), (%=) :: a - a - Bool
x %= y = (x y || x == y)
x % y = y x
x %= y = (y x || x == y)
Q: What's wrong? Why 'Ord'
Hi Dmitri,
I don't have answers for all your questions. But some, at least.
--- Dmitri O.Kondratiev [EMAIL PROTECTED] wrote:
-- Ok, then I can
derive MyOrd class directly from Ord:
class Ord a = MyOrd a where
(%), (%=), (%), (%=) :: a - a - Bool
x % y = x y
x %=
y =
Am Mittwoch, 26. Juli 2006 16:20 schrieb Dmitri O.Kondratiev:
On 7/25/06, Jared Updike [EMAIL PROTECTED] wrote:
I am trying to derive MyOrd class from Eq (Prelude):
class Eq a = MyOrd a where
(%=), (%), (%=) :: a - a - Bool
x %= y = (x y || x == y)
x % y
I am trying to derive MyOrd class from Eq (Prelude):
class Eq a = MyOrd a where
(%=), (%), (%=) :: a - a - Bool
x %= y = (x y || x == y)
x % y = y x
x %= y = (y x || x == y)
Q: What's wrong? Why 'Ord' gets into play here?
You are using which is a function
Sorry, left out an important verb, *hide*:
You can the prelude and thus the Ord class and make your own and
You can *hide* the prelude and thus the Ord class and make your own and
Jared.
--
http://www.updike.org/~jared/
reverse )-:
___
Hello Dmitri,
Tuesday, July 25, 2006, 8:15:41 PM, you wrote:
class Eq a = MyOrd a where
(%=), (%), (%=) :: a - a - Bool
x %= y = (x y || x == y)
x % y = y x
x %= y = (y x || x == y)
you are mixing definition of class and its (default) instance. try the
-cafe-
[EMAIL PROTECTED] On Behalf Of Bulat Ziganshin
Sent: Tuesday, July 25, 2006 9:46 AM
To: Dmitri O.Kondratiev
Cc: haskell-cafe@haskell.org
Subject: Re: [Haskell-cafe] Newbie Q: Deriving MyOrd from Eq problem
Hello Dmitri,
Tuesday, July 25, 2006, 8:15:41 PM, you wrote:
class Eq
