Re: Question about sets

2002-08-20 Thread Ketil Z. Malde
Scott J. [EMAIL PROTECTED] writes: I have a question. Why are sets not implemented in Haskell? What do you mean? Isn't http://www.haskell.org/ghc/docs/latest/html/hslibs/set.html sufficient? (Remember to tell GHC '-package data') -kzm -- If I haven't seen further, it is by

OT: broken mail threads

2002-08-20 Thread Lauri Alanko
I'm sorry to bring up such petty issues, but this has been nagging me for quite a long while now... The Haskell mailing lists have one rather unflattering characteristic: their mail threads are almost always broken. I'll elaborate. Most mail user agents arrange messages in threads, keeping

Re: Question about sets

2002-08-20 Thread Scott J.
As far a I know sets can implemented by implementing a list of anything(a list of all types) The sets Haskell does have are AFAIK sets of elements of the same type: these are not general sets. Scott - Original Message - From: Ketil Z. Malde [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent:

questions

2002-08-20 Thread Jonata Goulart
I'm trying to do a simple lex analyser in haskell I defined the function lexi that is intended to break a string into tokens returning them as a list but I received the following error: ERROR TesteEval.hs:20 - Syntax error in input (unexpected symbol restante) isLetter:: Char - Bool isLetter

Re: questions

2002-08-20 Thread Hal Daume III
There are three basic problems here. The first is the syntax error you see, the second and third will become available once you fix the syntax error. lexi (a:x) | isLetter a = token: lexi restante where S = takeWhile isLetterorDigit x line 20 -- restante =

Re: Question about sets

2002-08-20 Thread Jon Cast
Scott J. [EMAIL PROTECTED] wrote: As far a I know sets can implemented by implementing a list of anything(a list of all types) The sets Haskell does have are AFAIK sets of elements of the same type: these are not general sets. Ah. That's a static typing issue. However, I don't think it's

Re: Fw: Question about the use of an inner forall

2002-08-20 Thread oleg
Leon Smith wrote: On Friday 16 August 2002 23:57, Scott J. wrote: runST :: forall a ( forall s ST s a) - a ? In logic forall x forall y statement(x.y) is equivalent to: forall y forall x statement(x,y). Now, using a different argument, since s does not appear free on the R.H.S of

Leical and syntactic analyzer

2002-08-20 Thread Jonata Goulart
Does somebody know where can I find an example of a lexical and syntactic analyzer for arithmetic and conditional statements in Haskell? Thanks _ Chat with friends online, try MSN Messenger: http://messenger.msn.com